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anastassius [24]
3 years ago
6

A had $360 more than B. When A spent $144 and B spent half of his money, A had 6 times as much money as B, Find the ratio of the

amount of money A had at first to that of B. Find the ratio of the amount of money A had at first to that of B. Give your answer in its simplest form.
Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

13:3

Step-by-step explanation:

A=x B=y

first; x= 360+y

later;x= 216+y

A:B

216+y: 1/2y = 6: 1

216+y/y÷2 =6/1

216+y = 3y

y = 108

first; x =360+y

360 +108

468

A:B = 468:108

13:3

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Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

5x+y=335...(1)

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

7x+y=465...(2)

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

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\frac{2x}{2}=\frac{130}{2}

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Therefore, the each ticket costs $65.

Upon substituting x=65 in equation (1), we will get:

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