Find 75% of $36 and add it to $36. Convert 75% to a decimal and multiply it by 36. That's how you get 75% of 36.
Let's re-read the statement and question, and then break it down.
He charges a flat fee of $38, plus $22 per hour.
A flat fee of $38 is only a one-time pay, and will never be paid for again.
This means if after two hours, we only add $38 once overall, never more.
Every hour that goes by, he earns $22 each hour.
Now that we've broken this down, we can make an equation.
Let's do 1 hour.
1(22) + 38 = 22 + 38, = 60.
For 1 hour he earns $60.
Let's do 2 hours.
2(22) + 38 = 44 + 38, = 82.
For 2 hours he earns $82.
Let's do 3 hours.
3(22) + 38 = 66 + 38, = 104.
For 3 hours he earns $104.
Let's do 4 hours.
4(22) + 38 = 88 + 38, = 126.
For 4 hours he earns $126.
This is a pattern.
Now let's do 8 hours, which is the main question, "How much does he make in 8 hours?".
8(22) + 38 = 176 + 38, = 214.
For 8 hours he earns $214.
I hope this helps!
Answer:
area = (1/2) · (p + q) · h
Step-by-step explanation:
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
