All categories

3 years ago

One hectameter is =how much cm?A=100B=10000C=10D=1000

Mathematics

2 answers:

a_sh-v [17]3 years ago

6 0

Answer:

option B is correct because

1 hectameter is equal to 10000cm

Serggg [28]3 years ago

6 0

1 hectameter equals to 10,000 Centimeters. So your answer is choice B.

You might be interested in

If you have a 77.2% and you got 34% on a test and it’s worth 60% of your grade, what would you grade be now?

Rzqust [24]

Answer:

51.28%

Step-by-step explanation:

since the test is worth 60% of your grade, the rest is worth 40%

calculate your new grade by multiplying each grade percent (as written) by the percent of your grade (as a decimal):

77.2(0.4) = 30.88

34(0.6) = 20.4

then add them together: 30.88 + 20.4

4 0

1 year ago

Combine and simplify the radicals below √8 * √20

professor190 [17]

Here is my approach to this problem. :)

7 0

3 years ago

Find c1 and c2 such that M2+c1M+c2I2=0, where I2 is the identity 2×2 matrix and 0 is the zero matrix of appropriate dimension.

Katyanochek1 [597]

The question is missing parts. Here is the complete question.

Let M = $\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$ . Find $c_{1}$ and $c_{2}$ such that $M^{2}+c_{1}M+c_{2}I_{2}=0$ , where $I_{2}$ is the identity 2x2 matrix and 0 is the zero matrix of appropriate dimension.

Answer: $c_{1} = \frac{-16}{10}$

$c_{2}=\frac{-214}{10}$

Step-by-step explanation: Identity matrix is a sqaure matrix that has 1's along the main diagonal and 0 everywhere else. So, a 2x2 identity matrix is:

$\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

$M^{2} = \left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$

$M^{2}=\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]$

Solving equation:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+c_{1}\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right] +c_{2}\left[\begin{array}{cc}1&0\\0&1\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$

Multiplying a matrix and a scalar results in all the terms of the matrix multiplied by the scalar. You can only add matrices of the same dimensions.

So, the equation is:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+\left[\begin{array}{cc}6c_{1}&5c_{1}\\-1c_{1}&-4c_{1}\end{array}\right] +\left[\begin{array}{cc}c_{2}&0\\0&c_{2}\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$