Answer:
the length of the pipe should be 11.7 cm
Explanation:
given information:
the length of the taut, L = 62 cm = 0.62 m
wire's mass = 7.25 g = 7.25 x 10⁻³ kg
tension, F = 4310 N
speed sound,
= 344 m/s
to find the length of the pipe, we first calculate the speed of the wave on a string by:
v = √F/μ (1)
where
v = speed
F = tension
μ = linear density
μ = m/L, m is mass, and L is the length
thus,
v = √FL/m
= √(4310)(0.62)/(7.25 x 10⁻³)
= 607.11 m/s
now we find the frequency of the wire using
(n=1,2,3,.....) (2)
where
f = frequency
second overtone with very large amplitude, n = 3
so,

= 1468.81
now we can calculate the length of the pipe using the second equation. the frequency of the pipe and the wire is the same, therefore
n = 1, fundamental frequency

= 
= 0.117 m
= 11.7 cm