I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.
1 answer:
You might be interested in
Answer:
<h3>C no.</h3>Explanation:
<h2><em>M</em><em>a</em><em>r</em><em>k</em><em> </em><em>m</em><em>e</em><em> </em><em>m</em><em>e</em><em> </em><em>b</em><em>r</em><em>a</em><em>i</em><em>n</em><em>l</em><em>i</em><em>e</em><em>s</em><em>t</em><em> </em><em>p</em><em>l</em><em>z</em><em> </em><em>i</em><em> </em><em>r</em><em>e</em><em>a</em><em>l</em><em>l</em><em>y</em><em> </em><em>n</em><em>e</em><em>e</em><em>d</em><em> </em><em>i</em><em>t</em><em> </em><em>（⌒▽⌒）</em></h2>
Answer:
1) Time interval Blue Car Red Car
0 - 2 s Constant Velocity Increasing Velocity
2 - 3 s Constant Velocity Constant Velocity
3 - 5 s Constant Velocity Increasing Velocity
5 - 6 s Constant Velocity Decreasing Velocity
2) For Red and Blue car y₂ = 120 v = =
= 20 m/s
We get the same velocity for two cars because it is the average velocity of the car at the given interval of time. It is measured for initial and final position.
3) At t = 2s, the cars are the same position, and are moving at the same rate
Position - same
Velocity - same
The position-time graph shares the same spot for two cars.