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Elena L [17]
3 years ago
8

I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.

Physics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:It’s 5 I believe

Explanation: it says to round to the nearest thousandths, so it’ll be 5.

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Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the
Alborosie

Answer:

the diameter of the second pipe is 2.52 in

Explanation:  

Given the data in the question;

We know that; the rate of flow is the same;

so

Av1 = Av2

v ∝ √h

\frac{A1}{A2} = \frac{V2}{V1}

\frac{A1}{A2}  = √(  \frac{h2}{h1} )

( π/4.D1² / π/4.D2² ) = √(  \frac{h2}{h1} )

( D1² / D2² ) =  √(  \frac{2h1}{h1} ) since second is double of first

so

( D1² / D2² ) =  √(  \frac{2}{1} )  

3² / D2² =  √2

D2²√2  = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

3 0
3 years ago
If you are rowing a boat, you should be most concerned if you see a wave with which characteristic? help asap pls
3241004551 [841]
The best answer would be C. Amplitude is the measure of the distance between the crest and the center of the line, or the distance between the trough and the center of the line (like wave height). High waves are a sea danger, especially to small ships and rowboats.
4 0
3 years ago
A massless, rigid board is placed across two bathroom scales that are separated by a distance of 1.71 m. A person lies on the bo
Nata [24]

Answer:

Let the weight of the person be W and be located at a distance 'a' from the left scale as shown in the figure

Since the body is in equilibrium we can use equations of statics to analyse the problem.

Taking Sum of Moments about A we have

316\times 1.71-W\times a=0\\\\

Taking Sum of Moments about B we have

475\times 1.71-W\times (1.71-a)=0\\\\

Solving the above 2 equations for W and 'a' we get

316\times 1.71=W\times a\\\\475\times 1.71-W\times 1.71=-Wa\\\\\therefore W=\frac{316+475}{1}=791N\\\\\therefore a=\frac{316\times 1.71}{791}=0.683m

8 0
3 years ago
11. What is the power output of a student who completes 86 J of work in 4 seconds?
Vika [28.1K]

Answer:

P=21.5Watts

Explanation:

Use P=w/t

So, P=86j/4s = 21.5w

8 0
3 years ago
A blue liquid with a density of 1.2 g/cm3
lyudmila [28]
All you have to do is multiply that by the mass or volume.
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