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just olya [345]
3 years ago
8

An amino acid A, isolated from the acid-catalyzed hydrolysis of a peptide antibiotic, gave a positive ninhydrin test and had a s

pecific optical rotation (HCl solution) of 37.5 mL/(g·dm). Compound A was not identical to any of the 20 essential amino acids. The isoelectric point of compound A was found to be 9.4. Compound A can be prepared by the reaction of L-glutamine with Br2 in NaOH followed by acidification. Suggest a structure for A.
Chemistry
1 answer:
Ede4ka [16]3 years ago
7 0
The answer could be 23
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0.41g of neon is held in a 200. mL container at 11 °C. Calculate the pressure in atm.
777dan777 [17]

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

3 0
3 years ago
what is the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c
aniked [119]

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

Here, m = 49.5-gram = 0.0495 kg

Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

                  Q = 9.104 J

5 0
3 years ago
PLEASE HELP MEEE I WILL MARK BRAINLIST FOR THIS ITS SUPER SIMPLE....BUT U MUST TYPE EVERYTHING
Alina [70]

Answer:

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Explanation:

7 0
3 years ago
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When any salt is dissolved in water, the ionic bonds between the atoms must be broken in order for the salt to dissolve. The ene
Ksju [112]

Answer:

C released to the environment

Explanation:

I just did it in class

5 0
3 years ago
The molecular scene depicts a gaseous equilibrium mixture at 460°C for the reaction of H2 (blue) and I2 (purple) to form HI. Eac
soldi70 [24.7K]

Answer:

Therefore, the value of K_{p} is 2 \times 10^{9} and value of \Delta G^{o} is -53.2 kJ/mol.

Explanation:

4 0
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