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wlad13 [49]
2 years ago
13

Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m

east and 4 m north. Talia walked 2 m north, 6 m east, 3 m south, 4 m east, and 4 m north. Compare their displacements: Zamir’s displacement is Talia’s displacement.
Chemistry
2 answers:
egoroff_w [7]2 years ago
8 0

add then compare the two

yarga [219]2 years ago
5 0

Answer:

equal to

Explanation:

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How much heat is required to vaporize 43.9 g of acetone at its boiling point?
bogdanovich [222]
The heat required to vaporize 43.9 g  of acetone  at its boiling point is calculated as  below

 the heat of vaporization of acetone at its boiling  point is  29.1 kj/mole

find the moles of  acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

heat (Q) = moles x heat of vaporization

= 29.1 kj/mole  x 0.757 moles = 22.03 kj
5 0
3 years ago
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Acidity is a measure of the amount of dissolved hydroxide ions in a solution.
Gekata [30.6K]

The concentration of hydrogen ions in a solution is a measure of its acidity. So the correct option is (b) false.

When an Arrhenius acid is dissolved in water, hydrogen ions are produced:

H+(aq) + A- = HA + H2O (aq)

Here, H+ is the hydrogen cation, A- is the solvated anion, also known as the conjugate base, and HA is the non-dissociated acid. When an Arrhenius base is dissolved in water, hydroxide ions are produced:

BOH + H2O → B+(aq) + OH-(aq)

Is a material with at least one hydrogen atom that has the ability to split apart in an aqueous solution to produce an anion and an H + ion (a proton), creating an acidic solution. Bases are substances that, when dissolved in water, create hydroxide ions (OH) and a cation, resulting in a basic solution.

Learn more about hydrogen here:

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4 0
1 year ago
Which of the following chemical formulas represents a common acid?
wariber [46]
HCI is one of the most common acids out of the following
5 0
2 years ago
The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml
inn [45]
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>

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2 years ago
A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien
Paha777 [63]
It would be C because It will have a lower activation energy than Trial A.
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