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wlad13 [49]
2 years ago
13

Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m

east and 4 m north. Talia walked 2 m north, 6 m east, 3 m south, 4 m east, and 4 m north. Compare their displacements: Zamir’s displacement is Talia’s displacement.
Chemistry
2 answers:
egoroff_w [7]2 years ago
8 0

add then compare the two

yarga [219]2 years ago
5 0

Answer:

equal to

Explanation:

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Std 10th
kondaur [170]

Answer:

zinc and lead or copper and tin

Explanation:

these elements react both as an acid as well as a base

5 0
3 years ago
How are electrons arranged around an atom?
Schach [20]
They are arranged in shells
6 0
2 years ago
Which carbon skeleton represents an ether?<br><br> (gradpoint)
sineoko [7]

The present carbon skeleton in an ether is  C-C-C-O-C-C-C because ethers conatins C-O-C as functional group

7 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! WILL MARK BRAINLIEST!!!! A rigid steel container with a volume of 30 L is filled with oxygen to a pressure of 9.
GuDViN [60]

Answer:

12 atm

Explanation:

First, let us convert Celcius into Kelvin: 28.0 °C = 301.15 K and 129.0 °C = 402.15 K

For this question we must employ the Combined Gas Law: \frac{P_1V_1}{P_2V_2}=\frac{n_1RT_1}{n_2RT_2}, where P_1 is the initial pressure and P_2 is the new pressure.

We know that intitially, P=9 atm, V=30 L, and T=301.15K. From our problem, only temperature and pressure changes, while the number of moles, volume and the gas constant, R, stay the same, so they are irrelevant.

Thus, the filled out Combined Gas Law would be:

\frac{9 atm}{P_2}=\frac{301.15K}{402.15K}, where the volume, moles of gas, and R are cancelled out.

We can manipulate this equation to derive the new pressure. We find that

9atm≈0.74885P_2.  

This means that

P_2≈9/0.74885≈12 atm

4 0
2 years ago
What is he empirical formula for the compound that is of 1.85 moles of nitrogen and 4.63 miles of oxygen
BartSMP [9]

The empirical formula is N₂O₅.

The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.  

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the <em>molar ratio of N:O</em>.  

I like to summarize the calculations in a table.  

<u>Element</u> <u>Moles</u>  <u>Ratio¹ </u>  <u> ×2²  </u>  <u>Integers</u>³

     N        1.85    1             2             2

     O        4.63    2.503   5.005     5

¹To get the molar ratio, you divide each number of moles by the smallest number (1.85).

²Multiply these values by a number (2) that makes the numbers in the ratio close to integers.

³Round off the number in the ratio to integers (2 and 5).

The empirical formula is N₂O₅.

4 0
3 years ago
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