Answer:
12.07 g.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>2NH₃(g) + CO₂(g) → H₂NCONH₂(g) + H₂O(g),</em>
It is clear that 2.0 moles of NH₃ react with 1.0 mole of CO₂ to produce 1.0 mole of H₂NCONH₂ and 1.0 moles of H₂O.
- Consider the reaction proceeds at STP conditions:
At STP, 9.0 L of NH₃ react with an excess of CO₂ gas:
It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
<u><em>using cross multiplication:</em></u>
1.0 mol of NH₃ represents → 22.4 L.
??? mol of NH₃ represents → 9.0 L.
∴ 9.0 L of NH₃ represents = (1.0 mol)(9.0 L)/(22.4 L) = 0.4018 mol.
- To find the no. of moles of urea (H₂NCONH₂) produced:
<u><em>Using cross multiplication:</em></u>
2.0 mol of NH₃ produce → 1.0 mol of H₂NCONH₂, from stichiometry.
0.4018 mol of NH₃ produce → ??? mol of H₂NCONH₂.
∴ The no. of moles of H₂NCONH₂ = (1.0 mol)(0.4018 mol)/(2.0 mol) = 0.201 mol.
- Now, we can find the mass of H₂NCONH₂ produced:
<em>mass = n * molar mass</em> = (0.201 mol) * (60.06 g/mol) = <em>12.07 g.</em>
Na, C, and O so the answer is c. 3
The new volume of the gas is 16.3 L.
<h3>Boyle's law</h3>
Boyle's law states that the volume of a fixed mass of gas is inversely proportional to its pressure, at a constant temperature.
To calculate the new volume of the gas, we use the expression from Boyle's law.
Formula:
- PV = P'V'............. Equation 1
Where:
- P = initial pressure of gas
- V = Initial volume of gas
- P' = Final pressure of gas
- V' = Final volume of gas
Make V' the subject of the equation
- V' = PV/P'............. Equation 2
From the question,
- V = 20 L
- P = 2.5 atm
- P' = 3.1 atm
Substitute these values into equation 2
- V' = (20×2.5)/3.1
- V' = 16.13 L.
Hence, The new volume of the gas is 16.3 L.
Learn more about Boyle's law here: brainly.com/question/26040104
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