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ikadub [295]
3 years ago
8

Which of the two forces is greater the force on the firefly or the force on the bus explain your answer please I really need hel

p please
It’s due today please

Chemistry
1 answer:
maksim [4K]3 years ago
8 0

Answer: The force on the firefly

The unfortunate firefly hitting the bus does not change the velocity of the bus very much. Technically there is a change, but it's so very small and miniscule that it barely registers. To any casual observer not paying very close attention, they don't notice anything at all. So effectively the force on the firefly is a lot greater since the firefly got the worst end of the deal.

So in short, we look at the velocity of each object and see which velocity changed the most. In this case, the firefly's velocity changed from whatever speed it was flying to 0 when it stops flying all together. That's why the force is greater on the bug.

You might be interested in
Aluminum hydroxide + nitric acid ➡ aluminum nitrate + water
m_a_m_a [10]

Answer:

Chemical equation:

HNO₃ + Al(OH)₃   →  Al(NO₃)₃ + H₂O

Explanation:

Chemical equation:

HNO₃ + Al(OH)₃   →  Al(NO₃)₃ + H₂O

Balanced chemical equation:

3HNO₃ + Al(OH)₃   →  Al(NO₃)₃ + 3H₂O

Ionic equation:

3H⁺ + 3NO⁻₃(aq) + Al(OH)₃(s)   →  Al³⁺(aq) + 3NO₃⁻¹(aq) + 3H₂O(l)

Net ionic equation:

Al(OH)₃(s)  +  3H⁺(aq)     →  Al³⁺(aq) +  3H₂O(l)

The NO⁻₃ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

4 0
3 years ago
The density of ethanol is 0.79 g/mL. The density of acetic acid is 1.05 g/mL. Assuming that each
m_a_m_a [10]
The percent of the product would be 23
7 0
4 years ago
If .75 moles of ammonia is needed, how many grams of nitrogen will be consumed?
MrMuchimi

We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.

The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.

Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-

N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)

According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, \frac{1 X 0.75}{2} moles = 0.375 moles of nitrogen is required.

Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.

Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.


5 0
3 years ago
A
DIA [1.3K]
  • V_1=49.8mL
  • T_1=18°C=291K
  • T_2=83°C=356K

Using Charles law

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto V_2=V_1T_2\div T_1

\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}

\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}

\\ \sf\longmapsto V_2=60.9mL

5 0
3 years ago
How are molecules built?
RoseWind [281]
Bonding I'm guessing
6 0
3 years ago
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