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Ugo [173]
3 years ago
15

At 10 seconds, you used 55 Joules. Can you tell me the power?

Physics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

5.5

Explanation:

power =energy÷time

power=55÷10

power=5.5

SashulF [63]3 years ago
5 0
5.5 I think, I’m just decent at this stuff
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If the forces acting on an object are balanced, wihat must be true about the motion of this object?
wolverine [178]

The correct answer to the question is : D) Be moving at a constant velocity.

EXPLANATION:

As per Newton's first laws of motion, every body continues to be  at state of rest or of uniform motion in a straight line unless and until it is compelled by some external unbalanced forces acting on it.

Hence, it is the unbalanced force which changes the state of rest or motion of a body. Balanced force is responsible for keeping the body to be either in static equilibrium or in dynamic equilibrium.

As per the options given in the question, the last one is true for an object under balanced forces.

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3 years ago
Which planet has a moon with many sulfur volcanoes?
Murljashka [212]

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6 0
2 years ago
a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac
Katarina [22]

Answer:

a = change in v / change in time

= (5.2 - 11) / 3.1

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Explanation:

6 0
3 years ago
Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,
yarga [219]

Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

     = (9×10^9)×(q)/(24.0)

     = 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

                       R^2 = 9×r^2

E2 = k×q/(9×r^2)

     = k×q/(9×375000000q)

     = k/(9×375000000)

     = (9×10^9)/(9×375000000)

     = 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

5 0
3 years ago
How long does it for a car to cover 100 miles at 60 mi/hr? Use one of the following equations:
Mazyrski [523]
1 hour and 40 minutes
4 0
3 years ago
Read 2 more answers
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