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Ugo [173]
3 years ago
15

At 10 seconds, you used 55 Joules. Can you tell me the power?

Physics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

5.5

Explanation:

power =energy÷time

power=55÷10

power=5.5

SashulF [63]3 years ago
5 0
5.5 I think, I’m just decent at this stuff
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An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign
hammer [34]

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

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3 years ago
What Do You Already Know about Density? Material Design. Number each material and sort the items in order from lowest (1) to hig
Elena-2011 [213]

Answer:

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2. Flour - 593  kg/m^3

3. Wax - 900  kg/m^3

4. Wet sand - 2039 kg/m^3

5. Chalk - 2499 kg/m^3

6. Talcum Powder - 2776 kg/m^3

7. Copper - 8960  kg/m^3

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7 0
3 years ago
A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the
xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2

\hat{ECD} = tan^{-1} 2 = 63.43^o

This is also the angle ACB, so we can find the length AB:

tan(\hat{ACB}) = \frac{AB}{AC} = \frac{AB}{234}

2 = \frac{AB}{234}

AB = 2*234 = 468 m

So the height of the building is 468m

5 0
3 years ago
The work done on a box is 532 joules. The force applied to the box was 48 N. What was the displacement of the box? *
Semenov [28]

Explanation:

Work = force × displacement

532 J = 48 N × d

d ≈ 11 m

8 0
3 years ago
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