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Zina [86]
3 years ago
6

Which of the following is a physical change? burning a piece of wood rust forming on an iron fence sawing a piece of wood in hal

f a copper roof changing color from orange to green
Physics
1 answer:
maxonik [38]3 years ago
5 0
Sawing the piece of wood in half is a physical change,
because no new substances are formed that weren't there
before the sawing.

Burning wood produces carbon monoxide and carbon dioxide
that weren't there before the burning.  That's a chemical change.

Rust forming on iron is iron oxide that wasn't there before the
rusting.  That's a chemical change.

The green that appears on copper is copper oxide that wasn't
there before the green appeared.  That's a chemical change. 


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The Answer to this question would Be A

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3 years ago
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A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be pl
Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

Q = C_w BH^{3/2}

H = (\dfrac{Q}{C_wB})^{2/3}

H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}

H = 0.371\ m

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

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About how much time elapses between high tides on the same day?
Pani-rosa [81]
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Why do we call the microscope a compound light microscope
Ede4ka [16]

Explanation:

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3 years ago
An astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Kamila [148]

Answer:

The answer is

<h2>28 kg</h2>

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

m =  \frac{p}{v}  \\

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

m =  \frac{280}{10}  = 28 \\

We have the final answer as

<h3>28 kg</h3>

Hope this helps you

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