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Evgen [1.6K]
3 years ago
15

How many grams of a 26.9% sugar solution contain 49.0 g of sugar?

Chemistry
1 answer:
Ronch [10]3 years ago
6 0

Answer:

182.156g

Explanation:

grams = 49/.269 = 182.156g needed

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If I have 72 liters of argon gas held at a pressure of 3.4 atm and a temperature of 225k how many grams of argon do I have
andrezito [222]

Answer:

516.77 grams of Argon gas is present

Explanation:

Using the gas formula

PV = nRT

number of moles (n) = mass / molar weight or mass

P = pressure = 3.4 atm

V = volume = 72 L

R = gas constant = 0.082 L atm mol^-1 K^-1

T = temperature = 225 K

MM = molar mass of Ar = 38.984 g/mol

PV = mRT/ MM

m = PV MM / RT

m = 3.4 * 72 * 38.948 / 0.082 * 225

m =  9534.4704 / 18.45

m = 516.77 grams

the mass of Ar gas you have is 516.77 grams.

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