Aldol condensation involves two aldehydes or two ketones or an aldehyde and a ketone. The product of the reaction is shown in the image attached.
<h3>What is Aldol condensation?</h3>
Aldol condensation is a reaction that involves two aldehydes or two ketones or an aldehyde and a ketone. This reaction occurs at the carbonyl group as one of the carbonyl compounds is in the enolate form.
The product of the reaction is shown in the image attached. This gives the mechanism for the Aldol condensation of the compound 3‑methylbutanal.
Learn more about aldol condensation: brainly.com/question/9415260
Answer:
A. 68°F
B. 293K
Explanation:
The temperature (celsius) = 20.0°C
A. Conversion of the temperature in celsius to fahrenheit.
This is illustrated below:
°F = 9C/5 + 32
C = 20°C
°F = 9C/5 + 32
°F = 9x20/5 + 32
°F = 36 + 32
°F = 68°F
B. Temperature (Kelvin) = temperature (celsius) + 273
Temperature (celsius) = 20°C
Temperature (Kelvin) = 20°C + 273
Temperature (Kelvin) = 293K
Answer : Option D) The pH of the solution is 8.0.
Explanation : pOH of a solution is a measure of hydroxide ion
concentration in a particular solution. It gives the measure of alkalinity of a solution. Normally, aqueous solutions at 25°C have pOH which is less than 7 are usually alkaline, when pOH is found to be greater than 7 then they are acidic and when pOH will be equal to 7 then it is neutral.
pH + pOH = 14, this relationship is used to find pH of any unknown solution with given pOH value,
Here, we known pOH is 6.0, so we get,
pH = 14 - 6 = 8.0;
Hence, the pH will be 8.0.
Answer:
Answer: Change in speed = 11 m/sTime taken = 3.4sHence, acceleration = (11/3.4) m/s² = 3.235 m/s²
Explanation:
(winks and runs off)