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PilotLPTM [1.2K]
3 years ago
11

2 Iron(III) oxide (Fe2O3) is reduced by carbon on heating to give iron metal (Fe) and

Chemistry
1 answer:
astraxan [27]3 years ago
3 0
Cyrcucfucufxufxfucfucf
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Determine which of these properties would distinguish these two substances: (a) boiling point; (b) combustion analysis results;
Nutka1998 [239]

Answer:

(a) boiling point

(d) density at a given temperature and pressure.

Explanation:

Isomers are compounds that have the same molecular formula but different structural formulas. They differ in chemical and physical properties depending on the type of isomerism displayed by the compounds.

The compounds stated here are structural or constitutional isomers hence they possess different boiling points and densities at a given temperature and pressure owing to structural differences in the molecules.

Since they have the same molecular formula, they must yield the same result during combustion analysis and they must have the same molecular weight.

3 0
3 years ago
The solubility of Cr(NO3)3⋅9H2O in water is 208 g per 100 g of water at 15 ∘C. A solution of Cr(NO3)3⋅9H2O in water at 35 ∘C is
Zinaida [17]

Answer:

102g of crystals

Explanation:

When the Cr(NO₃)₃⋅9H₂O is dissolved in water at 15°C, the maximum mass that water will dissolve in the equilibrium is 208 g per 100g of water. When you heat the water, this mass will increases.

In this problem, at 35°C the water dissolves 310g in 100g of water, as in the equilibrium at 15°C the maximum mass is 208g, the mass of crystals that will form is:

310g - 208g = <em>102g of crystals</em>

<em>-Crystals are the Cr(NO₃)₃⋅9H₂O that is not dissolved-.</em>

I hope it helps!

5 0
3 years ago
What is the density of an object with a mass of 16 g and 3.0 ml
fomenos

Answer:

D = 5.3 g/mL

Explanation:

Density = Mass over Volume

D = m/V

Step 1: Define

D = unknown

m = 16 g

v = 3.0 mL

Step 2: Substitute and Evaluate

D = 16 g / 3.0 mL

D = 5.333333333 g/mL

Step 3: Simplify

We have 2 sig figs.

5.333333333 g/mL ≈ 5.3 g/mL

6 0
3 years ago
9. Suppose that 25.0 mL of a gas at 725 mm Hg and 20°C is converted to standard
storchak [24]

Answer:

V₂ = 22.23 mL

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 25 mL

Initial pressure = 725 mmHg (725/760 =0.954 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final pressure = standard = 1 atm

Final temperature = standard = 273.15 K

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁  P₂

V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm

V₂ =  6514.63 mL . atm . K  / 293 K . atm

V₂ = 22.23 mL

8 0
2 years ago
If vinegar is added to baking soda, the reaction Cu (s) + 2Ag(NO3) (aq) à 2Ag (s) + Cu(NO3)2 (aq) occurs. What evidence would in
Papessa [141]
The solution bubbles
8 0
3 years ago
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