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bixtya [17]
2 years ago
11

Question in image. Question from OSHA.

Engineering
2 answers:
olganol [36]2 years ago
7 0
The answer would be 2. I hope u have a good day!
marin [14]2 years ago
3 0

Answer:

2

Explanation:

my sister did this and its the answer

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Excessive looseness in steering and suspension components can cause _____
Phoenix [80]

Answer:

dynamic imbalance may cause the steering wheel to pull both directions

Explanation:

5 0
3 years ago
Technician A says that when the malfunction indicator light or service engine light is on you should retrieve the diagnostic tro
sergiy2304 [10]

Answer: A.

Explanation: Which of the following types of data helps a tech to determine the actual conditions under which a fault code is set? a test light. When it comes to troubleshooting an on-board diagnostic (OBD) code, the tech's best tools include all of these EXCEPT: ... original equipment manufacturer (OEM) diagnostic flow charts.

8 0
2 years ago
A wing generates a lift L when moving through sea-level air with a velocity U. How fast must the wing move through the air at an
vredina [299]

Answer:

V1 = 1.721 * V2

Explanation:

To start with, we assume that both lift forces are equal, such that

L2 = L1

1 is that of the level at 10000 m, and 2 is that of the level at sea level.

Next, we try and substitute the general formula for both forces such that

C(l).ρ1/2.V1².A = C(l).ρ2/2.V2².A

On further simplification, we have

ρ1.V1² = ρ2.V2², making V1 subject of formula, we have

V1 = √(ρ2/ρ1). V2²

Using the values of density for air at 10000 m and at sea level(source is US standard atmosphere), we have

V1 = √(1.225/0.4135) * V2

V1 = √2.9625 * V2

V1 = 1.721 * V2

4 0
2 years ago
Convert A'B'C'D' + A'B'C'D + A'B'CD' + A'BC'D + AB'C'D' + AB'C'D+ AB'CD' to SOP form
bazaltina [42]

Answer:

thats really hard how could you answerthis hhhhhhh

6 0
2 years ago
Read 2 more answers
Suppose there are 76 packets entering a queue at the same time. Each packet is of size 5 MiB. The link transmission rate is 2.1
tia_tia [17]

Answer:

938.7 milliseconds

Explanation:

Since the transmission rate is in bits, we will need to convert the packet size to Bits.

1 bytes = 8 bits

1 MiB = 2^20 bytes = 8 × 2^20 bits

5 MiB = 5 × 8 × 2^20 bits.

The formula for queueing delay of <em>n-th</em> packet is :  (n - 1) × L/R

where L :  packet size = 5 × 8 × 2^20 bits, n: packet number = 48 and R : transmission rate =  2.1 Gbps = 2.1 × 10^9 bits per second.

Therefore queueing delay for 48th packet = ( (48-1) ×5 × 8 × 2^20)/2.1 × 10^9

queueing delay for 48th packet = (47 ×40× 2^20)/2.1 × 10^9

queueing delay for 48th packet = 0.938725181 seconds

queueing delay for 48th packet = 938.725181 milliseconds = 938.7 milliseconds

4 0
3 years ago
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