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2 years ago

What computer program can you use to publish and share a research project with others?

Engineering

1 answer:

Ksenya-84 [330]2 years ago

4 0

Answer:

Word Online is the program

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A 100-ampere resistor bank is connected to a controller with conductor insulation rated 75°C. The resistors are not used in conj

Naily [24]

Answer:

answer

Explanation:

6 0

3 years ago

A small pad subjected to a shearing force is deformed at the top of the pad 0.12 in. The heigfit of the pad is 1.15 in. What is

ser-zykov [4K]

Answer:

Shearing strain will be 0.1039 radian

Explanation:

We have given change in length $\Delta L=0.12inch$

Length of the pad L = 1.15 inch

We have to find the shearing strain

Shearing strain is given by

$\alpha =tan^{-1}\frac{\Delta L}{L}=tan^{-1}\frac{0.12}{1.15}=5.9571^{\circ}$

Shearing strain is always in radian so we have to change angle in radian

So $5.9571\times \frac{\pi }{180}=0.1039radian$

6 0

3 years ago

Write the output expression for a NOR gate with inputs , , and .

mezya [45]

Answer:

Logic NOR Gate Equivalent

The Boolean expression for a logic NOR gate is denoted by a plus sign, ( + ) with a line or Overline, ( ‾‾ ) over the expression to signify the NOT or logical negation of the NOR gate giving us the Boolean expression of: A+B = Q.

4 0

2 years ago

Scanning the road can be thought of as

maw [93]

Answer:

Observational Skills

Explanation:

Observing the area also known as scanning the scene

5 0

3 years ago

Read 2 more answers

A heat pump operates on a Carnot heat pump cycle with a COP of 12.5. It keeps a space at 24°C by consuming 2.15 kW of power. Det

Vinil7 [7]

Answer:

a) $T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C)$ , b) $\dot Q_{H} = 26.875\,kW$

Explanation:

a) The Coefficient of Performance of the Carnot Heat Pump is:

$COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}$

After some algebraic handling, the temperature of the cold reservoir is determined:

$T_{H}-T_{L} = \frac{T_{H}}{COP_{HP}}$

$T_{L} = T_{H}\cdot \left(1-\frac{1}{COP_{HP}} \right)$

$T_{L} = (297.15\,K)\cdot \left(1-\frac{1}{12.5}\right)$

$T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C)$

b) The heating load provided by the heat pump is:

$\dot Q_{H} = COP_{HP}\cdot \dot W$

$\dot Q_{H} = (12.5)\cdot (2.15\,kW)$

$\dot Q_{H} = 26.875\,kW$

4 0

3 years ago