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Firdavs [7]
3 years ago
7

The Imager for Mars Pathfinder (IMP) is an imaging system. It has two camera channels. Each channel has color capability. This i

s provided by a set of filters. It was developed by a team led by the University of Arizona. Scientists and engineers from around the world were a part of the team. The system has three parts: (1) It has a camera head. (2) It has an extendable mast with electronic cabling. (3) It has two plug-in electronic cards. Each card plugs into a slot within the spacecraft.
What is the main idea of the numerical list in the second paragraph?
A. the electronic cabling in the imaging system
B. the three parts of the imaging system
C. the camera head of the imaging system
D. the two electronic cards in the imaging system
E. the extendable part of the imaging system
Engineering
1 answer:
Crank3 years ago
5 0
I believe it’s E. Not completely shure though
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True or False: The differential lock in an AWD-equipped vehicle can be used at any time.
Bingel [31]

the answer would be false

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3 years ago
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After testing a model of a fuel-efficient vehicle, scientists build a full-sized vehicle with improved fuel efficiency. Which st
Mazyrski [523]
B evaluate the solution. Sorry if I'm wrong.
4 0
3 years ago
A cylinder with a 6.0 in. diameter and 12.0 in. length is put under a compres-sive load of 150 kips. The modulus of elasticity f
jeka94

Answer:

Final Length = 11.992 in

Final Diameter = 6.001 in

Explanation:

First we calculate the cross-sectional area:

Area = A = πr² = π(3 in)² = 28.3 in²

Now, we calculate the stress:

Stress = Compressive Load/Area

Stress = - 150 kips/28.3 in²

Stress = -5.3 ksi

Now,

Modulus of Elasticity = Stress/Longitudinal Strain

8000 ksi = -5.3 ksi/Longitudinal Strain

Longitudinal Strain = -6.63 x 10⁻⁴

but,

Longitudinal Strain = (Final Length - Initial Length)/Initial Length

-6.63 x 10⁻⁴ = (Final Length - 12 in)/12 in

Final Length = (-6.63 x 10⁻⁴)(12 in) + 12 in

<u>Final Length = 11.992 in</u>

we know that:

Poisson's Ratio = - Lateral Strain/Longitudinal Strain

0.35 = - Lateral Strain/(- 6.63 x 10⁻⁴)

Lateral Strain = (0.35)(6.63 x 10⁻⁴)

Lateral Strain = 2.32 x 10⁻⁴

but,

Lateral Strain = (Final Diameter - Initial Diameter)/Initial Diameter

2.32 x 10⁻⁴ = (Final Diameter - 6 in)/6 in

Final Diameter = (2.32 x 10⁻⁴)(6 in) + 6 in

<u>Final Diameter = 6.001 in</u>

8 0
3 years ago
The minimum requirements for engineering documents are enumerated in
vladimir1956 [14]

Answer:

The answer will be Rule 61G15-23 F.A.C, relating to Seals.

Explanation:

According to the description given by: Florida administrative code&Florida administrative register the Minimum requirements for engineering documents are in the section 'Final 61G15-23'  from 11/3/2015. This document provides specifications of materials required for the safe operation of the system that is the result of engineering calculations, knowledge and experience.

8 0
3 years ago
If a dielectric material, such as teflon®, is placed between the plates of a parallel-plate capacitor without altering the struc
erastovalidia [21]

The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

<h3>What is capacitance?</h3>

A `is known to be a form of a device that is said to be used to save some amount of charges in any electrical circuit.

Note that the capacitor functions on the principle that the capacitance of a conductor is said to increases if an earthed conductor is  taken close to it.

Hence, The capacitance is affected is that the capacitance increases because of the insertion of Teflon.

See full question below

A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structure of the capacitor. The charge on the capacitor is held fixed. How is the electric field between the plates of the capacitor affected?

The electric field is not altered, because the structure remains unchanged.

The electric field becomes zero after the insertion of the Teflon®.

The electric field decreases because of the insertion of the Teflon®.

The electric field becomes infinite because of the insertion of the Teflon®.

The electric field increases because of the insertion of the Teflon®.

Learn more about  electric field  from

brainly.com/question/14781269

#SPJ1

4 0
2 years ago
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