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IgorC [24]
3 years ago
7

A compressor receives air at 290 K, 95 kPa and shaft work of 5.5 kW from a gasoline engine. It should deliver a mass flow rate o

f 0.01 kg/s air to a pipeline. Find the maximum possible exit pressure of the compressor.
Engineering
1 answer:
aev [14]3 years ago
3 0

Answer:

P2 = 3.9 MPa

Explanation:

Given that

T₁ = 290 K

P₁ = 95 KPa

Power P = 5.5 KW

mass flow rate  = 0.01 kg/s

solution

with the help of table A5

here air specific heat and adiabatic exponent is

Cp = 1.004 kJ/kg K

and k = 1.4

so

work rate will be

W = m × Cp × (T2 - T1)              ..........................1

here T2 = W ÷ ( m × Cp) + T1    

so T2 = 5.5 ÷ ( 0.001 × 1.004 ) + 290

T2 = 838 k

so final pressure will be here

P2 = P1 × (\frac{T2}{T1})^\frac{k}{k-1}        ..............2

P2 = 95 × (\frac{838}{290})^\frac{1.4}{1.4-1}

P2 = 3.9 MPa

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8 0
3 years ago
. For each of the following situations, determine if the diode below is in foward or reversebias(a) (2 points) V1 = 0 V, V2= 2V(
Mazyrski [523]

Assuming V1 is the anode and v2 the cathode (Anode is P region and Cathode is N)

Answer:

a) Reverse bias

b) Forward bias

c) Forward bias

Explanation:

Forward bias: It happens whenever the N region of the diode is more positive than the P region. Hence, the depletion zone increase ceasing the current through the circuit -> V1 -V2 < 0  

Reverse bias: It happens whenever the P region of the diode is more positive than the N region. In this case, the depletion zone begins to shrink, if enough voltage is applied current could go through the circuit -> V1 - V2 > 0

a) V = V1 - V2 = 0 - 2 = -2 -> -2 is smaller than zero therefore, we have reverse bias

b) V = V1 - V2 = 4.5 - 2.8 = 1.7 -> 1.7 is greater than zero therefore, we have forward bias

c9 V = V1 - V2 = -1 - -1.3 = 0.3 -> 0.3 is greater than zero therefore, we have forward bias

6 0
3 years ago
Reference sources reveal that a workpiece material has a unit horsepower of 1.6 hp/in3/min. For a turning operation, the cutting
Troyanec [42]

The question is incomplete. We have to calculate :

a). the cutting force

b). volumetric metal removal rate, MRR

c). the horsepower required at the cut

d). if the power efficiency of the machine tool is 90%, determine the motor horsepower

Solution :

Given :

Cutting velocity (v) = 500 ft/min

                               = 500 x 12 in/min

                               = 6000 in/min

Feed , f = 0.025 in/rev

Depth of cut, d = 0.2 in

b). Volumetric material removal rate, MRR = v.f.d

                                                                      = 6000 x 0.025 x 0.2

                                                                      = 30 $in^3 / min$

c). Horsepower required = MRR x unit horsepower

                                         = 30 x 1.6

                                         = 48 hp

a). Cutting force,

$F=\frac{power}{cuting \ velocity}$

    $=\frac{48 \times 550}{500 /60}$                (1 hp = 550 ft lbf /sec)

   = 3168 lbf

d). Machine HP required

  $=\frac{HP}{\eta}$

 $=\frac{48}{0.9}$

= 53.33 HP

6 0
3 years ago
Do volts or amps kill you.
svetoff [14.1K]
11,000 volts can be fatal to a human
4 0
3 years ago
1. How many types of pumps are present?​
Butoxors [25]

Answer:

three

Explanation:

There are three basic types of pumps: positive-displacement, centrifugal and axial-flow pumps.

3 0
3 years ago
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