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IgorLugansk [536]
3 years ago
14

As the water molecules re-freeze, what happens to the salt ions that are mixed in with the water?

Chemistry
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

Explanation:

Since salt is composed of two ions Na+ and Cl- it will attract to the opposite poles of the water and form a ion-dipole bond. This will cause the phenomenon freezing point depression where as the name states it will take a lower tempertature to freeze it. So instead of freezing at 0 degrees c it will freeze at a negative 2 or so on.

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What is the mass of oxygen in 25.0 grams of potassium permanganate , KMnO4?
Katen [24]

Answer:

10.76 grams

Explanation:

Given that the amount of KMnO_4 is 25.0 grams.

Mass of 1 mole of KMnO_4 = 158 grams

The number of atoms in 1 mole of KMnO_4 is 4.

Mass of oxygen in 1 mole of KMnO_4 = 16\times 4 = 68 grams.

Here, 158 grams of KMnO_4 has 68 grams of oxygen

So, the amount of oxygen in 1 gram of KMnO_4 = 68/158 grams

Therefore,  the amount of oxygen in 1 gram of KMnO_4 = \frac {68}{158}\times 25 grams

=10.76 grams

Hence, 25 grams of KMnO_4 has 10.76 grams of oxygen.

3 0
2 years ago
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What would be the correct answer please help!
bogdanovich [222]

Answer:

first number is the correct answer

6 0
3 years ago
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What did early scientists assume that the polar caps had in common?
Vilka [71]

Answer:

They assumed they both had water.

Explanation:

Because they only could look at it through telescopes that were not advanced

3 0
3 years ago
What is the wavelength of light that has a frequency of 3.7 x 1014 Hz? Show all work!!!
kramer

Answer:

Explanation:

f=\frac{c}{\lambda}=>\lambda=\frac{c}{f}=\frac{300x10^8\frac{m}{s}}{3.7*10^{14}\frac{1}{s}}=810.8108*10^{-9}m

3 0
3 years ago
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The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure = 198 kPa

P_2 = final pressure = 225 kPa

T_1 = initial temperature = 27^oC=273+27=300K

T_2 = final temperature = ?

Now put all the given values in the above equation, we get:

\frac{198kPa}{300K}=\frac{225kPa}{T_2}

T_2=340.9K\approx 341K

Therefore, the temperature of the air in the tire is, 341 K

5 0
3 years ago
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