Answer:
K = 0,00000135 = 1.35 * 10^-6
Explanation:
Step 1: Data given
The equilibrium constant, K, for any reaction is defined as the concentrations of the products raised by their coefficients divided by the concentrations of the reactants raised by their coefficients. In this case, the concentrations are given as partial pressures.
The partial pressures of H2O = 0.0500 atm
The partial pressures of H2 = 0.00150 atm
The partial pressures of O2 = 0.00150 atm
Step 2: The balanced equation
2H2O(g) ⇆ 2H2(g) + O2(g)
Step 3: Calculate K
K = [O2][H2]² / [H2O]²
K = 0.00150 * 0.00150² / 0.0500²
K = 0,00000135 = 1.35 * 10^-6
B).Proton acceptor did that help at all
Copper Sulfate (CuSO4) compound is basically comprised of Copper (II) ion and Sulfate ion. Ions are C<span>u2</span>+ and S<span>O4 2</span><span>−</span>.
<em>ANSWER:</em><em>Cu 2+ and SO4 2-</em>
Answer:
a. -7.44 °C
Explanation:
Hello there!
In this case, since the freezing point depression formula is:
Thus, since the Van't Hoff's factor is 2 for KCl as it ionizes in K⁺ and Cl⁻, the molarity is 2.0 m (2.0mol/1.0kg) and the freezing point depression constant is 1.86 °C/m, we calculate the freezing point depression as follows:
Therefore, the answer is a. -7.44 °C.
Regards!
Answer:
Ca is larger than the Ca2+ because Ca2+ has a greater positive charge and electrons repel the nucleus.