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Inessa [10]
3 years ago
8

How many atoms are in 3.5 grams of copper

Chemistry
2 answers:
storchak [24]3 years ago
7 0
Avegadro's number = 6.02 x10^23 atoms
so
3.5g x 1mol/63.55g Cu x 6.02 x 10^23/ 1mol=3.32 x 10^22 atoms
slega [8]3 years ago
5 0

<u>Answer:</u> For the given mass of copper, the number of atoms are 3.3121\times 10^{22}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of copper = 3.5 g

Molar mass of copper = 63.55 g/mol

Putting values in above equation, we get:

\text{Moles of copper}=\frac{3.5g}{63.55g/mol}=0.055mol

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of atoms

So, 0.055 moles of copper will contain = 0.055\times 6.022\times 10^{23}=3.3121\times 10^{22} number of atoms.

Hence, for the given mass of copper, the number of atoms are 3.3121\times 10^{22}

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Marta_Voda [28]

Answer:

i think the answer is A....

Explanation:

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8 0
3 years ago
Compute the reactance of a 0.450 H inductor at the frequency of 60.0 Hz. Express your answer in ohms.
vlada-n [284]

Answer:

169.67Ω

Explanation:

This question is asking for the inductive reactance, which is calculated as follows:

X(L) = 2πfL

Where;

X(L) = inductive reactance (Ω)

f = frequency (Hz)

π = 3.142

L = inductance (Henry)

Given the information provided, f = 60Hz, L = 0.450H

X(L) = 2πfL

X(L) = 2 × 3.142 × 60 × 0.450

X(L) = 6.284 × 60 × 0.450

X(L) = 6.284 × 27

X(L) = 169.668

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7 0
3 years ago
Which of these statements is correct? a. Particles in a suspension will settle out if left undisturbed. b. A solution is heterog
tatuchka [14]

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4 0
3 years ago
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Answer:

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sln Na2SO4:

∴ V = 450 mL

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aliina [53]

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3 0
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