<span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)
3 mol 3mol
4 mol x mol
x=4*3/3= 4.0 mol
</span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)<span>
2 mol 3 mol
14 mol x mol
x=14*3/2= 21.0 mol</span>
Answer:
By a factor of 12
Explanation:
For the reaction;
A + 2B → products
The rate law is;
rate = k[A]²[B]
As you can see, the rate is proportional to the square of the concentration of A and the of the concentration of B
.
Let's say initially, [A] = x, [B] = y
The rate law in this case is equal to;
rate1 = k. x².y
Now you double the concentration of A and triple the concentration of B.
[A] = 2x, [B] = 3y
The new rate law is given as;
rate2 = k . (2x)². (3y)
rate2 = k . 4x² . 3y
rate2 = 12 k . x² . y
Comparing rate 2 and rate 1, the ratio is given as; rate 2/ rate 1 = 12
Therefore the rate has increased by a factor of 12.
Answer= C) CN contains a covalent bond.
