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sweet-ann [11.9K]
3 years ago
12

Explain, in terms of electron configuration, why oxygen atoms and sulfur atoms form compounds with similar molecular structures

Chemistry
1 answer:
Fynjy0 [20]3 years ago
3 0
Oxygen atoms and sulfur atoms form compounds with similar molecular structures because if you look at these two, they both have six electrons in their valence shells. Therefore, they will generally react in much the same manner. I hope this helps you on your assignment.
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How many moles of oxygen react with 12 moles of aluminum
mina [271]

Answer:

If, for example, we want to know how many moles of oxygen will react with 17.6 mol ... Write the balanced chemical reaction for the combustion of C 5H 12

Explanation:

8 0
3 years ago
Question 6
hodyreva [135]

Answer:

0.00688 moles

Explanation:

The molarity ratio looks like this:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the values into the equation and simplify to find moles.

27.5 mL / 1,000 = 0.0275 L

Molarity = moles / volume                         <----- Molarity ratio

0.250 M = moles / 0.0275 L                      <----- Insert values

0.00688 = moles                                       <----- Multiply both sides by 0.0275

4 0
2 years ago
In the copper – silver nitrate lab Copper medals and silver nitrate solution reacted to produce silver metal and copper (II) nit
Nataly [62]

Answer:

Percent Yield = 97.75 %

Explanation:

1 MOLE = It is equal to the molar mass of the substance

1 mole of Cu = 63.54 g (Molar Mass of Cu = 63.54 g/mole)

1 mole of AgNO3 = 170 g (Molar Mass of AgNO3 = 170 g/mol)

Given Mass of AgNO3 = 1.41 g

Given Mass of Cu = 2.93 g

<em><u>Second step : Find the limiting Reagent (which is in less amount) </u></em>

Balanced Chemical equation :

Cu + 2AgNO_{3} \rightarrow Cu(NO_{3})_{2}+2Ag

This means

1 mole of Cu will react with  = 2 mole of AgNO3

63.54 g of Cu  reacts with = 2 x 170 g of AgNO3

1 g  of Cu  reacts with = (2 x 170)/63.54 of AgNO3

= \frac{170\times 2}{63.54}

= 5.35 g of AgNO3

2.93 g should reacts with = 2.93 x 5.35 = 15.67 g of AgNO3

Available AgNO3 = 1.41 g

So , AgNO3 is less than required = limiting reagent

Now the reaction occur 1.41 g of AgNO3

Now, Limiting reagent will decide How much Silver(Ag) Metal will form

2 mole of AgNO3 will produce = 2 mole of Ag

1 mole of AgNO3 will produce = 1 mole of Ag

170 g  AgNO3 will produce = 107.86 mole of Ag(Molar mass of Ag = 107.86)

1 g AgNO3 will produce =

\frac{107.86}{170}

1.41 g of AgNO3 will produce =

\frac{107.86\times 1.41}{170}

= 0.89 g

Yield\ Percent = \frac{Actual\ Yield}{Theoritical\ Yield}\times 100

Actual yield = 0.87 g

Theoritical yield = 0.89 g

Yield\ Percent = \frac{0.87}{0.89}\times 100

Percent Yield = 97.75 %

5 0
3 years ago
Why a plant can survive longer than bacteria
Arlecino [84]

Answer:

Bacteria are vital in keeping nitrogen cycling through the ecosystem, and nitrogen is vital to plant growth. Without bacteria around to break down biological waste, it would build up. And dead organisms wouldn't return their nutrients back to the system

Explanation:

3 0
2 years ago
Which isotope of lead has a double magic number? (1) Pb-206 (2) Pb-207 (3) Pb-208 (4) Pb-209
antiseptic1488 [7]
It is Pb-208, answer 3.
4 0
3 years ago
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