Answer:
To make one gallon of 5% methyl alcohol we require 115.2oz of water and 12.8oz of 50% methyl alcohol solution
Explanation:
Required solution = 1 gallon of 5% methyl alcohol or1 gallon 5/100 moles per dm3 of methyl alcohol
Number of moles in required solution = 0.05moles/dm3 × 1gallon
Where 1 gallon = 0.00378dm3
= 0.05moles/dm3 × 0.00378dm3 = 1.892×10-4 moles
The quantity of the 50% solution with Paul required is given by
50% = 50/100 = 0.5 moles/dm3
Volume of 50% solution of methyl alcohol that contains 1.892×10-4 moles
= concentration = (Number of moles)/(volume of dm3) of solution thus
Volume of solution = (Number of moles)/(concentration)
1.892/0.5 =3.785×10-4dm3 of the 50% solution is required to make 1 gallon of 5% solution
3.785×10-4dm3 = 12.8oz
Thus to make 1 gallon or 128oz solution of 5% alcohol requires
128oz - 12.8 oz = 115.2oz of water and 12.8oz of 50% methyl alcohol solution
<span>361.4 pm is the length of the edge of the unit cell.
First, let's calculate the average volume each atom is taking. Start with calculating how many moles of copper we have in a cubic centimeter by looking up the atomic weight.
Atomic weight copper = 63.546
Now divide the mass by the atomic weight, getting
8.94 g / 63.546 g/mol = 0.140685488 mol
And multiply by Avogadro's number to get the number of atoms:
0.140685488 * 6.022140857x10^23 = 8.472278233x10^22
Now examine the face-centered cubic unit cell to see how many atoms worth of space it consumes. There is 1 atom at each of the 8 corners and each of those atoms is shared between 8 unit cells for for a space consumption of 8/8 = 1 atom. And there are 6 faces, each with an atom in the center, each of which is shared between 2 unit cells for a space consumption of 6/2 = 3 atoms. So each unit cell consumes as much space as 4 atoms. Let's divide the number of atoms in that cubic centimeter by 4 to determine the number of unit cells in that volume.
8.472278233x10^22 / 4 = 2.118069558x10^22
Now calculate the volume each unit cell occupies.
1 cm^3 / 2.118069558x10^22 = 4.721280262x10^-23 cm^3
Let's get the cube root to get the length of an edge.
(4.721280262x10^-23 cm^3)^(1/3) = 3.61426x10^-08 cm
Now let's convert from cm to pm.
3.61426x10^-08 cm / 100 cm/m * 1x10^12 pm/m = 361.4 pm
Doing an independent search for the Crystallographic Features of Copper, I see that the Lattice Parameter for copper at at 293 K is 3.6147 x 10^-10 m which is in very close agreement with the calculated amount above. And since metals expand and contract with heat and cold, I assume the slight difference in values is due to the density figure given being determined at a temperature lower than 293 K.</span>
It’s A: C2H2N (basically you count how many C, H and N there are)
The answer is (1). Temperature is directly proportional to the average kinetic energy of the particles in any given sample of matter, and it is usually defined along those lines.