Answer:
Here is a picture of all the elements
Your solution steps look correct, but the answer was not completed. Given that QR = 33.8 and PQ = 57.6, and Q is the right angle, then tan P = opposite / adjacent = QR / PQ = 33.8 / 57.6 = 0.586.
Then tan P = 0.586
Angle P = tan^-1 (0.586) = 30.4 degrees.
Answer:
Option C = 1.72 mol
Explanation:
Given data:
Mass of KF = 100 g
Moles of KF = ?
Solution:
First of all we have to calculate the molar mass of KF.
Molar mass of KF = 39.0983 g/mol + 18.998403 g/mol
Molar mass of KF = 58. 0967 g/mol
Formula:
Number of moles = mass/molar mass
Number of moles = 100 g/ 58.0967 g/mol
Number of moles = 1.72 mol
<u>Ans: Mass of NaNO3 = 574 g</u>
<u>Given:</u>
Volume of NaNO3, V = 4.50 L
Molarity of NaNO3, M = 1.50 M i.e. 1.50 moles/L
Molar mass of NaNO3 = 85.00 g/mol
<u>To determine:</u>
The mass of NaNO3
<u>Explanation:</u>
Molarity of a solution can be expressed as the number of moles of the solute in a liter volume of solution
Molarity of NaNO3 = moles of NaNO3/volume of solution in L
1.50 moles/L = moles/4.50 L
moles NaNO3 = 1.50 *4.50 = 6.75 moles
Now, moles of NaNO3 = mass of NaNO3/molar mass NaNO3
mass of NaNO3 = moles * molar mass =
= 6.75 moles * 85.00 g/mole
= 573.75 g = 574 g
