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Daniel [21]
3 years ago
15

What are the names of the components ( each shown with a leader and a line) of a circuit in the diagram. NAME ALL 4

Chemistry
1 answer:
3241004551 [841]3 years ago
7 0
It is an open circuit because the metal does not complete the electric flow
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How many sulfur atoms are there in 21.0 g of al2s3?
ValentinkaMS [17]

Given the mass of aluminum sulfideAl_{2}S_{3} = 21.0 g

Molar mass of Al_{2}S_{3} = 2 * Molar mass of Al + 3 *molar mass of S = 2(27g/mol)+3(32.g/mol)=150.g/mol

Calculating the moles of Al_{2}S_{3}:

21.0 g *\frac{1 mol}{150 g} = 0.14 mol Al_{2}S_{3}

Each mole Al_{2}S_{3} has 3 mol S.

Each mole S constitutes 6.022*10^{23} atoms of S

Calculating atoms of S in 0.14 mol Al_{2}S_{3}:

0.14 mol Al_{2}S_{3} *\frac{3mol S}{1 mol Al_{2}S_{3}  }*\frac{6.022*10^{23}atoms S }{1 mol S}

= 2.53 * 10^{23} atoms of S

3 0
3 years ago
Calculate Ecell at 80 ºC for a voltaic cell based on the following redox reaction: H2(g, 1.25 atm) + 2AgCl(s) → 2Ag(s) + 2H+(aq,
iris [78.8K]

Answer:

Ecell = +0.25V

Explanation:

the half-cell reactions for a voltanic cell

cathode(reduction): 2H⁺(aq) + 2e⁻ ------- H₂(g)

anode(oxidation): 2AgCl(s) ------- 2Ag⁺(aq) + 2Cl⁻ + 2e⁻

we have the standard cell potential E⁺cell = 0.18V at 80C respectively

Q = [H⁺]/[Cl⁻]

sub for [H+] = 0.10M and [Cl-] = 1.5M

Q= 0.1M/1.5M

Q = 0.067

Ecell = E⁺cell - \frac{0.059}{n} logQ

= 0.18 - \frac{0.056}{1} log 0.067

0.18- 0.059(-1.174)

Ecell = +0.25V

6 0
3 years ago
Question 4 of 5
Nastasia [14]

Answer:

B

Explanation:

7 0
2 years ago
Read 2 more answers
Help me please i'm begging you its DUE today its super easy
NARA [144]

Answer:

The answer will be listed below.

Explanation:

Kinetic Energy- Energy of motion, increases with mass

Potential Energy- Stored energy, increases with height

Both- Increases with velocity

6 0
2 years ago
PLS HELP ME I HAVE TILL 12
MariettaO [177]

Answer:

alright bud lets see hmm.... the answer is a. 90.5kpa

Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

3 0
3 years ago
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