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natta225 [31]
3 years ago
14

Put the events in order to explain how radios work.

Physics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

The person in front of me is right

Explanation:

There’s my proof

Bogdan [553]3 years ago
3 0

Answer:

1. Sound waves are changed into electrical

2. Radio waves are released by transmitter

by radios

3. Radio waves are converted to sound waves

Explanation:

You might be interested in
A 300 g bird is flying along at 6.0 m/s and sees a 10 g insect heading straight towards it with a speed of 30 m/s. The bird open
Gelneren [198K]

Answer:

(a): The bird speed after swallowing the insect is V= 4.83 m/s

(b): The impulse on the bird is I= 0.3 kg m/s

(c): The force between the bird and the insect is F= 20 N

Explanation:

ma= 0.3 kg

va= 6 m/s

mb= 0.01kg

vb= 30 m/s

(ma*va - mb*vb) / (ma+mb) = V

V= 4.83 m/s (a)

I= mb * vb

I= 0.3 kg m/s  (b)

F*t= I

F= I/t

F= 20 N (c)

5 0
3 years ago
The next two questions refer to this situation: A rectangular loop with sides of length a= 1.00 cm and b= 2.70 cm is placed near
alisha [4.7K]

Answer:

a) 1.007 * 10^{-7} V.m , into the page

b) -5.39 * 10^{-8} V, counterclockwise

Explanation:

a) d\Phi = B.dA\\\\B_r = \frac{\mu_0I}{2\pi r}\\\\dA = b.dr\\\\\Phi = \int\limits^b_a {B.dA} = \int\limits^{a+d}_d {\frac{\mu_0I}{2\pi r}.b.dr} =\frac{\mu_0I}{2\pi }.b.ln(\frac{a+d}{d} )\\

At t = 2.90, I = 3.62 + 1.49 * (2.90)^2 = 16.15 A

\Phi = \frac{4\pi * 10^{-7}*16.15*0.027}{2\pi} ln(1.46/0.46) = 1.007 * 10^{-7} V.m

Direction is into the page.

b) emf = -d\Phi/dt = -\frac{\mu_0}{2\pi }.b.ln(\frac{a+d}{d}).(2.98t)= \\=-\frac{4\pi * 10^{-7}*0.027}{2\pi} ln(1.46/0.46)*2.98*2.90= -5.39 * 10^{-8} V

Direction is counterclockwise.

8 0
3 years ago
What is the period of a wave if the frequency is? 5 Hz
viktelen [127]

Answer:  If the woodpecker drums upon a tree 5 times in one second, then the frequency is 5 Hz; each drum must endure for one-fifth a second, so the period is 0.2 s.

6 0
4 years ago
How fast is sound when traveling through water?
IgorLugansk [536]

Sound travels 1,480 meters per second, which is about 4.3 times as fast as air. Sound travels much slowly in air. This has to do with the frequency, intensity and amplitude of waves, which are affected differently in water and air.

4 0
3 years ago
How much force is required to accelerate an 8.6kg wagon by 15 m/s ?
OverLord2011 [107]

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

<h3>What is force?</h3>

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

  • Mass of the rock m = 8.6kg
  • Acceleration a = 15m/s²
  • Force F = ?

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

Learn more about force here: brainly.com/question/27196358

#SPJ1

7 0
2 years ago
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