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Ludmilka [50]
2 years ago
6

The table shows the number of candid pictures of students for the yearbook for two consecutive years. Year Number of Photos 2015

236 2016 214 What was the percent of decrease in the number of candid student pictures from 2015 to 2016, rounded to the nearest tenth?
Mathematics
1 answer:
Elena-2011 [213]2 years ago
4 0

Answer:

The percentage decrease in the number candid student pictures for the yearbook from 2015 to 2016 is approximately 9.3 percent

Step-by-step explanation:

The given data can be presented as follows

Year           {}                      Number of Photos

2015           {}                      236

2016           {}                      214

The percentage decrease in the number of candid pictures is give by the following formula

Percentage \ Decrease = \dfrac{Original \ Value- New \ Value}{Original \ Value}  \times 100

Where;

Original value for the number of pictures = 236

New value for the number of pictures = 214

Substituting the values into the equation for the percentage decrease gives;

Percentage \ Decrease = \dfrac{236- 214}{236}  \times 100 = \dfrac{550}{59} \ percent\approx 9.3 \%

The percentage decrease is approximately 9.3 percent.

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A scatter plot showed a positive correlation for 11 bowlers. As the number of strikes, s, a bowler made in a game increased, the
almond37 [142]

Answer:

s = 4

Step-by-step explanation:

The equation for the line of best fit for the data is p=25s+40.

Where p is no. of points and s is no. fo strikes

We need to find the number of strikes made by a bowler with 140 points.

Put p = 140

p=25s+40

140 = 25s+40

Subtract 40 to both sides,

140-40 = 25s+40-40

100 = 25s

⇒ s = 4

So, there are 4 strikes made by a bowler with 140 points.

5 0
2 years ago
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ki77a [65]

Answer:

not me doing this 4 points:00

Step-by-step explanation:

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2 years ago
Shara collected two different data sets and label them dataset S and data said T.
Kamila [148]

Answer:

What are you asking?

Step-by-step explanation:

4 0
3 years ago
What is the slope in the Y intercept of the line on the graph below
Archy [21]

Answer:

just by looking at the graph you can see that the y int is one, so that eliminates two answers already. Then the slope is rise over run. (best thing to remember in math. rise over run) so pick two points. (0, 1) and (4,0) were the first ones i saw. to get from those two points you go from (0,1) over 4 (thats your run) and from there down 1 (thats your rise) to get to (0,4). You would then do rise over run (and because your rise goes down its negative) to get -1/4 as your slope. The answer is slope= -1/4, Y intercept = 1

6 0
2 years ago
HELP!
maksim [4K]

<u>Part A</u>

<u />4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3

So, the x-intercepts are \boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}

<u>Part B</u>

The vertex will be a minimum because the coefficient of x^2 is positive.

The x-coordinate of the vertex is x=-\frac{-7}{2(4)}=\frac{7}{8}

Substituting this back into the function, we get f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}

So, the coordinates of the vertex are \boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}

<u>Part C</u>

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

7 0
1 year ago
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