I'm pretty sure that you need to multiply pie times the radius of the circle
Just put a period between everything 2.9.3.3
Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.
Answer:
I don't use Geogebra, but the following procedure should work.
Step-by-step explanation:
Construct a circle A with point B on the circumference.
- Use the POINT and SEGMENT TOOLS to create a circle with centre B and radius BA.
- Use the POINT tool to mark points D and E where the circles intersect.
- Use the SEGMENT tool to draw segments from C to D, C to E, and D to E.
You have just created equilateral ∆CDE inscribed in circle A.
Answer:
i would say true
Step-by-step explanation: