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3 years ago

A rock falls off the edge of a building and falls for 10 seconds. What was

Physics

2 answers:

solmaris [256]3 years ago

4 0

Ricks velocity would be zooomin out because it would fall off so strongly so it’d change and it’s weight too

In-s [12.5K]3 years ago

3 0

Assuming the rock falls straight down, we can determine that this rock is under the influence of solely gravity (the rock is in free fall). therefore, the rock will accelerate at 9.8 m/s^2 (acceleration due to gravity). we can utilize this to solve for vf by plugging our known variables into the kinematics equation vf=v0+at. this will lead us to vf=0+9.8(10), or vf=98 m/s^2. this answer, while correct, seems a tad bit unreasonable, so you should mention to your teacher to consider the feasibility of his physics problems.

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The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to c

Korolek [52]

Answer: C) divide: distance ÷ velocity

Explanation:

The velocity $V$ equation is distance $d$ divided by time $t$ :

$V=\frac{d}{t}$

If we isolate $t$ we will have:

$t=\frac{d}{V}$

Hence, the correct option is C: distance divided by velocity.

7 0

3 years ago

In a cell protein synthesis is the primary function of

Elena-2011 [213]

In a cell, protein synthesis is the primary function of the ribosomes, found in both eukaryotic and prokaryotic cells.

A Ribosome is a cell organelle that makes protein. The location of the ribosome in a cell determine the kind of protein it makes. If the ribosome is attached to the endoplasmic reticulum, the proteins made are utilized both within and outside the cell. If the ribosome is in the cytoplasm, floating freely, then the kind of protein made will be utilized within the cell only.

8 0

3 years ago

The heat capacity of object B is twice that of object A. Initially A is at 300 K and B at 450 K. They are placed in thermal cont

ivann1987 [24]

Answer:

The final temperature of both objects is 400 K

Explanation:

The quantity of heat transferred per unit mass is given by;

Q = cΔT

where;

c is the specific heat capacity

ΔT is the change in temperature

The heat transferred by the object A per unit mass is given by;

Q(A) = caΔT

where;

ca is the specific heat capacity of object A

The heat transferred by the object B per unit mass is given by;

Q(B) = cbΔT

where;

cb is the specific heat capacity of object B

The heat lost by object B is equal to heat gained by object A

Q(A) = -Q(B)

But heat capacity of object B is twice that of object A

The final temperature of the two objects is given by

$T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}$

But heat capacity of object B is twice that of object A

$T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K$