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3 years ago

A rock falls off the edge of a building and falls for 10 seconds. What was

Physics

2 answers:

solmaris [256]3 years ago

4 0

Ricks velocity would be zooomin out because it would fall off so strongly so it’d change and it’s weight too

In-s [12.5K]3 years ago

3 0

Assuming the rock falls straight down, we can determine that this rock is under the influence of solely gravity (the rock is in free fall). therefore, the rock will accelerate at 9.8 m/s^2 (acceleration due to gravity). we can utilize this to solve for vf by plugging our known variables into the kinematics equation vf=v0+at. this will lead us to vf=0+9.8(10), or vf=98 m/s^2. this answer, while correct, seems a tad bit unreasonable, so you should mention to your teacher to consider the feasibility of his physics problems.

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Emily uses a rifle to shoot a bullet at a target. The bullet has a mass of 13 grams. The rifle has a mass of 3,500 grams. When s

sp2606 [1]

Force exerted by the bullet = mass * acceleration = 0.013 * 850 = 11.05 Newtons.

the rifle exerts same force in opposite direction so we have

11.05 = 3.5 * a
acceleration = 11.05 / 3.5 = 3.16 m /s^-2

4 0

3 years ago

Read 2 more answers

A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha

Slav-nsk [51]

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3 years ago

A body of mass 2.7 kg makes an elastic collision with another body at rest and continues to move in the original direction but w

kramer

Answer:

1.35 kg

2.67 ms⁻¹

Explanation:

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = ?

$v_{1i}$ = initial velocity of the first body before collision = $v$

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

$v_{1f}$ = final velocity of the first body after collision =

using conservation of momentum equation

$m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}$

Using conservation of kinetic energy

$m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35$

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = 1.35 kg

$v_{1i}$ = initial velocity of the first body before collision = 4 ms⁻¹

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

Speed of the center of mass of two-body system is given as

$v_{cm} = \frac{(m_{1} v_{1i} + m_{2} v_{2i})}{(m_{1} + m_{2})}\\v_{cm} = \frac{((2.7) (4) + (1.35) (0))}{(2.7 + 1.35)}\\\\v_{cm} = 2.67$ ms⁻¹

8 0

3 years ago

In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.

SOVA2 [1]

Answer:

he wavelength is different (greater) than the wavelength of the incident photon

Explanation:

The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes

To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon

3 0

3 years ago

A knight moves on a chessboard two squares up, down, left, or right followedby one square in one of the two directions perpendic

Contact [7]

Answer:

Explanation:

Check attachment for solution.

Generally the movement of the knight is L, i.e (2,1), (1,2),(-1,2),(1,-2) etc.

So using Pythagoras theorem

x^2+y^2=1^2+2^2

x^2+y^2=5

Then, the knight will make one movement when the displacement is √5.

So let take a look at other positions

(1,0),(0,1),(-1,0), (0,-1).

Then, for us to have this kind of movement, the knight has to make 3 movements.

When the displacement is 1, then it will make 3 movement.

Let examine other positions

(2,2) or(-2,-2) or (2,-2) or (-2,2)

When the displacement is √8

Then, the movement of the knight is 4.

Let examine other points

(2,0) or (0,2) or (-2,0) or (0,-2)

When the displacement is 2.

The knight make 2 movement

5 0

3 years ago