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olga nikolaevna [1]
2 years ago
11

What current is used to power the Untied States power grid? O alternating current O direct current​

Physics
2 answers:
QveST [7]2 years ago
4 0

Answer:

alternating

Explanation:

it was right on my quiz

Alina [70]2 years ago
3 0

Answer:

Alternating

Explanation:

It is alternating because it is easy to distribute long distance.

Direct current is found in batteries and have large voltage drop over distance.

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yes ,what's the question

and if the question is why

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Because it defines the boundaries of the system
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A 1300 kg steel beam is supported by two ropes. (Figure
Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

  • the net horizontal force acting on the beam is

R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0

where R_1,R_2 are the magnitudes of the tensions in ropes 1 and 2, respectively;

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R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0

where m=1300\,\rm kg and g=9.8\frac{\rm m}{\mathrm s^2}.

Eliminating R_2, we have

\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2

R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2

-R_1 \sin(50^\circ) = -\dfrac{mg}2

R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}

Solve for R_2.

\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0

\dfrac{R_2}2 = -mg\cot(110^\circ)

R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}

8 0
1 year ago
Someone solve this please...........​
Natali [406]

Answer:

The answer is 4x³ + 6x²

<u>-TheUnknownScientist</u><u> 72</u>

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2 years ago
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Lear vv
F
B
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greatest pressure ^^


I’m really sorry if I’m wrong
7 0
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