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Alexxx [7]
3 years ago
13

Please can someone help me with this maths question ‍♀️: Solve 5x+2=20

Mathematics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

x = 18/5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

5x + 2 = 20

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 2 on both sides:                    5x = 18
  2. Divide 5 on both sides:                        x = 18/5

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    5(18/5) + 2 = 20
  2. Multiply:                               18 + 2 = 20
  3. Add:                                     20 = 20

Here we see that 20 does indeed equal 20.

∴ x = 18/5 is a solution to the equation.

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Drupady [299]

Answer:

x = 55°

y = 70°

z = 125°

Step-by-step explanation:

Based on the Isosceles triangle theorem, since two sides of the triangle are congruent, therefore, the angles opposite to each of the equal sides are congruent.

Thus:

x = 180° - 125° (angles on a straight line/linear pair)

x = 55°

If x = 55°, the other base angle will also be 55°.

Therefore,

y = 180° - (55° + 55°) (sum of ∆)

y = 70°.

z = x + y (exterior angle of a ∆ theorem)

z = 55° + 70° (substitution)

z = 125°

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3 years ago
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tia_tia [17]

Hello!

Space = 5 cm + 10cm + 10cm + 20cm + 22cm + 30cm => space = 15cm + 10cm + 20cm + 22cm + 30cm => space = 25cm + 20cm + 22cm + 30cm => space = 45cm + 22cm + 30cm => space = 67cm + 30cm => space = 97cm²

Good luck! :)

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Answer:

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Step-by-step explanation:

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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.​
Norma-Jean [14]

Answer:

<u>Arc Measure</u>:  equal to the measure of its corresponding central angle.

<u>Formulas</u>

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)

\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2

\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}

<h3><u>Question 39</u></h3>

Given:

  • r = 7 in
  • \theta = 90°

Substitute the given values into the formulas:

Arc AB = 90°

\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)

<h3><u>Question 40</u></h3>

Given:

  • r = 6 ft
  • \theta = 120°

Substitute the given values into the formulas:

Arc AB = 120°

\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)

<h3><u>Question 41</u></h3>

Given:

  • r = 12 cm
  • \theta = 45°

Substitute the given values into the formulas:

Arc AB = 45°

\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)

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An important problem in industry is shipment damage. A windshield factory ships its product by truck and determines that it cann
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Answer:

Option f) None of these

Step-by-step explanation:

We are given the following data set:

Sample size, n = 12

Sample mean  = 9.4

Sample standard deviation = 0.64

Confidence interval:

\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}

Putting the values, we get,

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