The circumference of the circle after t seconds = 25.12 t
Given data,
The radius of each circular wave will increase by four centimeters per second (cm/s)
In 1 second of circular wave radius = 4cm
In 1*t second of circular wave radius = 4t cm
As a result, the radius of the circular wave after t seconds is 4t cm.
We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.
As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t
= 8πt
( Taking π = 3.14 )
As a result, the circumference of the circle after t seconds = 8πt
= 3.14t
= 25.12t
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Answer:
But once the core runs out of hydrogen, the star starts to contract again briefly, until a shell of hydrogen around the core becomes hot enough to fuse into helium. When this happens, the radiation pushes the outer layers of the star far out into space, turning the star into a red giant
Explanation:
Correct?
F(friction) = u F(normal)
so, F(friction) = (.30)(60*9.81) = 177 N
F = ma
so, 177 = (60)a, a = 177/60 = 2.9m/s^2
v(final)^2 = v(initial)^2+2ax
so, 0 = 1.5^2 + 2(-2.9)x, x = 2.25/(2*-2.9) = -.38793 the negative indicates that the direction of accel is opposite of direction of speed.
-0.39 meters is the answer.
Answer:
Explanation:
Let the velocity of lander with respect to earth be v .
In relativistic mechanism the expression for relative velocity is
v_r = 
Given u = .6c , v_r = .8 c
Substituting the values
.8c = 
.8c-.48v = v - .6c
v = .946c
b )
Distance in terms of time = .2 ly
In relativistic mechanism , expression for relativistic time is given by the following relation
t = 
Substituting v = .946c
t₀ = .2
t = 
.2 / √.1050
= .62 ly
distance to the Earth at the time of lander launch, as observed by the aliens will be .62 ly.
