The ball may attracted to the magnet.
<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
- From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
- As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
- Steel is a magnetic material.
- Magnetic materials gets attracted to the magnet at both the North and South pole.
- This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.
So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.
Learn more about the bar magnet:
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Answer:
DONTKNOW NEED CAREER FILD FIRST TO ANWSER
Explanation:
In a projectile, the horizontal acceleration is zero. The velocity remains constant at all times. However, the <u>vertical acceleration</u> is -9.81m/s^2.
Hope this helps!
There's so much going on here, in a short period of time.
<u>Before the kick</u>, as the foot swings toward the ball . . .
-- The net force on the ball is zero. That's why it just lays there and
does not accelerate in any direction.
-- The net force on the foot is 500N, originating in the leg, causing it to
accelerate toward the ball.
<u>During the kick</u> ... the 0.1 second or so that the foot is in contact with the ball ...
-- The net force on the ball is 500N. That's what makes it accelerate from
just laying there to taking off on a high arc.
-- The net force on the foot is zero ... 500N from the leg, pointing forward,
and 500N as the reaction force from the ball, pointing backward.
That's how the leg's speed remains constant ... creating a dent in the ball
until the ball accelerates to match the speed of the foot, and then drawing
out of the dent, as the ball accelerates to exceed the speed of the foot and
draw away from it.
