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kari74 [83]
3 years ago
15

An ionic compound is found to contain 10.9% magnesium, 31.8% chlorine and 57.3% oxygen. What is the empirical formula for this c

ompound?
Chemistry
2 answers:
Luda [366]3 years ago
7 0
Mg 10.9g/24.31=0.018/0.018=1
Cl 31.8g/35.45=0.897/0.018=49.83=50
O 57.3g/16.00=3.581/0.018=198.94=199

empirical formula=MgCl50O199

I think it's right
Jet001 [13]3 years ago
7 0

Answer:

The empirical formula is MgClO₈.

Explanation:

To find the empirical formula, which is the minimum integer ratio between the atoms in a compound, we have to follow some steps.

Step 1: Divide each percentage by the atomic mass of the element

Mg: \frac{10.9}{24.3} =0.449

Cl: \frac{31.8}{35.5} =0.896

O: \frac{57.3}{16.0} =3.58

Step 2: We divide all the numbers by the smallest

In this case, the smallest number is 0.449

Mg: \frac{0.449}{0.449} =1.00

Cl: \frac{0.896}{0.449} =2.00

O: \frac{3.58}{0.449} =7.97\approx 8

Step 3: We incorporate these numbers as the atomicities in the empirical formula

The empirical formula is MgClO₈.

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The density of benzene is 0.879g/mL. The volume (with 1 decimal) of 131.9g sample of benzene is how many mL?
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Explanation:

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Step 2: Calculate the volume of the sample of benzene

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<em />

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<em>∴ M = (mass/molar mass)of NiCl₂/(V of the solution (L)).</em>

<em></em>

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