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melamori03 [73]

3 years ago

6

Q: How can variations in the rate of interaction between the hydrosphere and the atmosphere result in global climate change?

1 answer:

Evgesh-ka [11]3 years ago

6 0

D is the correct answer on edge

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PLS ANSWER REAL ANSWERS ONLY

Julli [10]

Answer:

Who is moving the fastest: Green triangle

What is the slope of Blue Diamonds: 5/6 or 5/7, can’t tell completely

<h2><u>Hope This helped!</u></h2>

7 0

3 years ago

Three students attempt to define what it means for lines lll and mmm to be perpendicular. Can you match the teacher's comments t

Ber [7]

Incompletevquestion. However, I inferred from a general perspective about perpendicular lines.

<u>Explanation:</u>

Put simply, <u>perpendicular lines</u> are lines that are at right angles (90°) to each other. Thus, we could say based on this definition that for lines lll and mmm to be perpendicular they intersect and be at right angles (90°) to each other as <u>found on the attached image.</u>

3 0

3 years ago

the goat weighs 900 N and is 1 meter from the fulcrum. The strongman pulls down on the lever 3 meters from the fulcrum. What is

garik1379 [7]

Answer: The smallest effort = 300N

Explanation:

Using one of the condition for the attainment of equilibrium:

Clockwise moment = anticlockwise moments

900 × 1 = 3 × M

Where M = the weight of the strong man

3M = 900

M = 900/3 = 300N

Therefore, 300N is the smallest effort that the strongman can use to lift the goat

6 0

3 years ago

a block of mass m slides along a frictionless track with speed vm. It collides with a stationary block of mass M. Find an expres

shusha [124]

Answer:

Part a) When collision is perfectly inelastic

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b) When collision is perfectly elastic

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

Explanation:

Part a)

As we know that collision is perfectly inelastic

so here we will have

$mv_m = (m + M)v$

so we have

$v = \frac{mv_m}{m + M}$

now we know that in order to complete the circle we will have

$v = \sqrt{5Rg}$

$\frac{mv_m}{m + M} = \sqrt{5Rg}$

now we have

$v_m = \frac{m + M}{m} \sqrt{5Rg}$

Part b)

Now we know that collision is perfectly elastic

so we will have

$v = \frac{2mv_m}{m + M}$

now we have

$\sqrt{5Rg} = \frac{2mv_m}{m + M}$

$v_m = \frac{m + M}{2m}\sqrt{5Rg}$

6 0

4 years ago

The laboratory test that detects neutropenia is

bixtya [17]

It's absolute neutropihil count, also called ANC

4 0

4 years ago