All categories

3 years ago

Plsss plsss plsss helppppp ASAP thank u ❤️

Physics

2 answers:

Aleonysh [2.5K]3 years ago

5 0

Answer:

7. (D) uniformly accelerated vertical motion

8. (A) zero

9. (A) zero

10. (C) parabolic

ivolga24 [154]3 years ago

5 0

Answer:

7.Uniformly accelerated vertical motion

8.0m/s²

9.9.8m/s

10.parabolic

11.vertical component.

You might be interested in

Four weather satellites are orbiting the Earth at a height of 825 kilometers. Some characteristics of the satellites are shown i

ratelena [41]

Answer:

Explanation:

The gravitational force between any two objects is affected by the masses of the objects and the distance between them. The greater the masses of the objects are, the stronger the gravitational force is.

Since all four of the satellites are the same distance from the Earth's surface, only their masses affect the strength of the gravitational force. At 903 kilograms, satellite D has the greatest mass, so the gravitational force pulling it toward the Earth is the greatest.

4 0

3 years ago

An enemy spaceship is moving toward your starfighter with a speed, as measured in your frame, of 0.400c. The enemy ship fires a

kvasek [131]

Answer:

0.859375c

31.03 seconds

Explanation:

v' = Velocity of my ship = 0.4 c

u = Velocity of rocket = 0.7 c

c = Speed of light = $3\times 10^8\ m/s$

s = Distance between my ship and enemy ship = $8\times 10^6\ km$

Relativistic addition of speed is given by

$v=\dfrac{v'+u}{1+\dfrac{uv'}{c^2}}\\\Rightarrow v=\dfrac{0.7+0.4}{1+\dfrac{0.7c\times 0.4c}{c^2}}\\\Rightarrow v=0.859375\ c$

The speed of the missile is 0.859375c

Time is given by

$t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{8\times 10^9}{0.859375\times 3\times 10^8}\\\Rightarrow t=31.03\ s$

It will take 31.03 seconds to reach me.

6 0

3 years ago

A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle du

White raven [17]

Answer:

$a. \phi _B=3.0528\times10^-^3T\ m^2\\ \\b. \phi_B=1.83299\times10^-^3T\ m^2\\\\c.\phi_B=0$

Explanation:

#Consider a circular area of radius $R=2.98cm$ in the xy-plane at z=0. This means all the are vector points toward the +ve z-axis.

a. first, find the magnetic flux if the magnetic field has a magnitude of $B=0.23T$ and points toward the +ve z-axis. The angle between the magnetic field and the area is $\theta=0$ . Hence the magnetic flux:-

$\phi _B=\int {\bar B} . d\bar A \\=\int BdAcos(\theta)=BAcos(0)=BA\\\\=\pi R^2B=\pi(6.50\times10^-^3m)^2(0.230T)\\=3.0528\times10^-^3 T\ m^2$

Hence flux magnitude in $+z$ direction is $3.0528\times10^-^3T \ m^2$

b. We now find the magnetic flux when the field has a magnitude of <em>B=0.230T</em> and points at an angle of $\theta=53.1\textdegree$ from the $+z$ direction.

Magnetic flux is calculated as:

$\phi _B=\int\bar B \bar dA\\=\int BdAcos (\theta)=BAcos(0)=BA\\=\pi R^2B=\pi(6.50\times 10^-^2m)^2(0.230T)\\=1.83299\times 10^-^3 T \ m^2$

Hence the flux at an angle of $53.1\textdegree$ is $1.83299\times 10^-^3T \ m^2$

c. We now need to find the magnetic flux if the field has a magnitue of B=0.230T and points in the direction of +y-direction. As with the previous parts, the magnetic flux will be calculated as:

$\phi_B= \int\bar B \times d\bar A\\=\int BdAcos(\theta)\\=BAcos(90\textdegree)\\=0$

Hence the magnetic flux in the +y-direction is zero.

3 0

3 years ago

Suppose that the Millennium Falcon orbits the Death Star 20,000m above the Star’s surface. Calculate the circular orbit velocity

Nataly [62]

Answer:

18.4 m/s

Explanation:

The gravitational force between the Death Star and the Millenium Falcon is equal to the centripetal force that keeps the Millenium Falcon in circular orbit:

$G\frac{Mm}{(R+h)^2}=m\frac{v^2}{R+h}$