Answer:
Must be put in to break the bonds in the reactants and the energy that is released upon making the bonds in the products.
Explanation:
The heat energy is absorbed to break the chemical bonds, which are responsible for the attractive interactions between atoms and molecules, and which gives stability to chemical compounds. While the heat energy is released upon making the bonds in the chemical compounds.
<span>Forecasting the time of, location, and magnitude of a seismic event does not prevent
the event from happening, but it can help us reduce the destruction caused by
A) earthquakes.</span>
The potential energy of the car when it let go is 20,000 J.
The speed of the car at the bottom of the ramp is 20 m/s.
The given parameters;
- <em>mass of the car, m = 100 kg</em>
- <em>height of the car, h = 20 m</em>
<em />
The potential energy of the car is calculated as follows;
P.E = mgh
P.E = 100 x 10 x 20
P.E = 20,000 J
The speed of the car at the bottom of the ramp is calculated as follows;
Learn more here:brainly.com/question/18597080
Given
Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied
force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient
of kinetic friction µk = 0.3. If a force P
is applied to the body, no relative motion will take place until the applied
force is equal to the force of friction Ff, which is acting opposite to the
direction of motion. Magnitude of static force of friction between block A and
block B, Fs = µsN, where N is
reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA +
mB)a,
6 = (20 / 32.2 + 50 / 32.2)a
2.173a = 6
A = 2.76 ft/s^2
To check slipping occurs between block A and block B, consider block A:
P – Ff = mAaA
6 – Ff = 1.71
Ff = 4.29 lb
And also,
N = wA. We know static friction,
Fs = µsN
Fs = 0.4 x 20
Fs = 8lb
Frictional force is less than static friction. Ff < Fs
<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of
block B aB = 2.76 ft/s^2</span>
