Answer:
0.01395mol Cr2O3
Explanation:
the molar mass of Cr2O3 is 151.9904 g/mol
2.12g Cr2O3 x 1 mol/151.9904g = 0.01395mol Cr2O3
Answer:
1.Balance the equation.
2.Convert units of a given substance to moles.
3.Using the mole ratio, calculate the moles of substance yielded by the reaction.
4.Convert moles of wanted substance to desired units.
Explanation:
Answer:
0.32 M
Explanation:
Step 1: Write the balanced reaction at equilibrium
Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)
Step 2: Calculate the concentration of Ag⁺ at equilibrium
We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.
Keq = [Ag⁺]² × [S²⁻]
[Ag⁺] = √{Keq / [S²⁻]}
[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M
Answer:
2Al + 3H2SO4 → Al2(SO4)3 + 3H2
2Fe + 3Cl2 → 2FeCl3
Explanation:
1. (SO4) 3 you see this 3 it means that 3 must be behind H2SO4. So now it's 3H2SO4.
2. If 3 is now behind one H2, it must be behind the other.
So now it's 3H2.
3. Al2 (SO4) 3 has 2 ahead of Al which means there will be 2Al in the reactants.
1. FeCl3 has 3 ahead of Cl, and Cl2 has 2. Which means that behind FeCl3 goes 2, and behind Cl2 goes 3 so now we have equated all Cl.
2. Since it is now 2FeCl3, we know that there must be 2 in the second Fe. It's 2Fe now.
Nothing it just changes temp as it is protected by glass layers