Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is
To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
The question is incomplete, here is the complete question:
A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of chemist's working solution is
<u>Explanation:</u>
To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:
where,
are the molarity and volume of the stock magnesium fluoride solution
are the molarity and volume of chemist's magnesium fluoride solution
We are given:
Putting values in above equation, we get:
Hence, the concentration of chemist's working solution is
The dimensions of room are . Thus, volume of room will be:
Converting to
Since,
Thus,
Now, concentration of carbon monoxide in the urban apartment is , thus, mass of carbon monoxide can be calculated as follows:
Rearranging,
Putting the values,
converting
Since, thus,
Therefore, mass of carbon monoxide present in the room is .