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jeka57 [31]
3 years ago
5

8. How much heat is released when 85.0 g of steam condense to liquid water?

Chemistry
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

199920J

Explanation:

Given parameters:

Mass of steam  = 85g

Unknown:

Heat released when the liquid is condensed  = ?

Solution:

The heat released by the substance is given as;

         H  = mL

H is the heat released

m is the mass

L is the latent heat of steam  = 2352J/g

Heat released  = 85 x 2352  = 199920J

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Answer:

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3 years ago
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
What is the formula for Silver (I) chloride?
Kisachek [45]
The formula for Silver (I) chloride is: AgCl
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And your unbalanced and balanced equations are correct.

(sorry I went on a tangent with the diatomic rules hopefully it will help you in the future though) 
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3 years ago
6. What is a polyatomic ion? (You should also memorize the name, formula, and charge of the polyatomic ions listed in the lectur
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