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andrew11 [14]
2 years ago
12

The fulcrum of a first-class lever divides its 9.0 m arm into two sections—a 6.0 m arm and a 3.0 m arm. You place a rock weighin

g 98.1 N on the 3.0 m end. How much force do you need to exert on the 6.0 end to balance the lever?
a)49 N
b)200 N
c)880 N
d)1,800 N
Physics
1 answer:
nexus9112 [7]2 years ago
6 0
For balancing the lever, force on both the sides shall be equal. so,
Force on 3 m end = m × a = 3 × 98.1 = 294.3

Now, on 6 m end, it would be: = 294.3/6 = 49.05
After rounding-off to the nearest hundredth value, it would be: 49 N

Finally, Option A would be your correct answer.

Hope this helps!
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The 480 g bar is rotating as shown what is the angular momentum of the bar about the axle?
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On a similar problem wherein instead of 480 g, a 650 gram of bar is used:

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<span>The direction of the angular momentum vector - pseudovector, actually - would be straight out of the diagram toward the viewer. </span>

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