The solid product from reaction of sulfuric acid with sucrose is?
- Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.
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<h3>RELATED TO THE QUESTION </h3>
- <u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
- <u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.
- <u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.
- <u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.
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<h3>→XxKim02xX</h3>
Answer:
Qsp > Ksp, BaCO3 will precipitate
Explanation:
The equation of the reaction is;
Na2CO3 + BaBr2 -------> 2NaBr + BaCO3
Since BaCO3 may form a precipitate we can determine the Qsp of the system.
Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles
concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M
Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles
concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M
Hence;
[Ba^2+] = 6.7 * 10^-5 M
[CO3^2-] = 9.1 * 10^-4 M
Qsp = [6.7 * 10^-5] [9.1 * 10^-4]
Qsp = 6.1 * 10^-8
But, Ksp for BaCO3 is 5.1*10^-9.
Since Qsp > Ksp, BaCO3 will precipitate
Answer:
CH
Explanation:
We have to obtain the mass of carbon and hydrogen in CO2 and H2O respectively.
For carbon in CO2;
0.845 * 12/44 = 0.23 g
For hydrogen in H20;
0.173 * 2/18 = 0.019 g
We convert the masses to moles of carbon and hydrogen
For carbon - 0.23/ 12 = 0.019 moles
For hydrogen - 0.019/1 = 0.019 moles
Dividing by 0.019 moles for carbon and hydrogen we have the emperical formula of the compound as CH
Answer:
V₂ = 27 L
Explanation:
Given data:
Initial volume = 15 L
Initial temperature = 125 K
Final temperature = 225 K
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 15 L × 225K / 125 k
V₂ = 3375 L.K / 125 K
V₂ = 27 L
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