Answer:
awnsers should be added to know to show additional
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
Answer:
W=2 MW
Explanation:
Given that
COP= 2.5
Heat extracted from 85°C
Qa= 5 MW
Lets heat supplied at 150°C = Qr
The power input to heat pump = W
From first law of thermodynamics
Qr= Qa+ W
We know that COP of heat pump given as
![COP=\dfrac{Qr}{W}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BQr%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
W=2 MW
For Carnot heat pump
![COP=\dfrac{T_2}{T_2-T_1}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BT_2%7D%7BT_2-T_1%7D)
![2.5=\dfrac{T_2}{T_2-(273+85)}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7BT_2%7D%7BT_2-%28273%2B85%29%7D)
2.5 T₂ - 895= T₂
T₂=596.66 K
T₂=323.6 °C
Answer:
Suction and exhaust processes do not affect the performance of Otto cycle.
Explanation:
Step1
Inlet and exhaust flow processes are not including in the Otto cycle because the effect and nature of both the process are same in opposite direction.
Step2
Inlet process or the suction process is the process of suction of working fluid inside the cylinder. The suction process is the constant pressure process. The exhaust process is the process of exhaust out at constant pressure.
Step3
The suction and exhaust process have same work and heat in opposite direction. So, net effect of suction and exhaust processes cancels out. The suction and exhaust processes are shown below in P-V diagram of Otto cycle:
Process 0-1 is suction process and process 1-0 is exhaust process.
Answer:
230.4W
Explanation:
Heat transfer by conduction consists of the transport of energy in the form of heat through solids, in this case a jacket.
the equation is as follows
![Q=\frac{KA(T2-T1)}{L} \\](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7BKA%28T2-T1%29%7D%7BL%7D%20%5C%5C)
Where
Q=heat
k=conductivity=0.04
A=Area=1.8m^2
T2=33C
T1=1C
L=thickness=1cm=0.01m![Q=\frac{(0.04)(1.8m^2)(33-1)}{0.01m}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%280.04%29%281.8m%5E2%29%2833-1%29%7D%7B0.01m%7D)
Q=230.4W
the skier loses heat at the rate of 230.4W