Answer:
A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;
B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;
C)cout<<fixed<<5.789E12;
D)cout<<left<<setw(7)<<67;
Explanation:
Stream Manipulators are functions specifically designed to be used in conjunction with the insertion (<<) and extraction (>>) operators on stream objects in C++ programming while the 'cout' statement is used to display the output of a C++to the standard output device.
setw: used to specify the minimum number of character positions on the output field
setprecision: Sets the decimal precision to be used to format floating-point values on output operations.
fixed: is used to set the floatfield format flag for the specified str stream.
left: adjust output to the left.
A) To display the number 34.789 in a field of eight spaces with two decimal places of precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;
B) To display the number 7.0 in a field of six spaces with three decimal places of precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;
C) To print out the number 5.789e+12 in fixed-point notation. cout<<fixed<<5.789E12;
(D) To display the number 67 left-justified in a field of six spaces. cout<<left<<setw(7)<<67;
Answer: Metals are good thermal conductors because they have close packaged metal ions in their lattice structure but in polymers they have discontinuous structure which make them poor as a conductor.
Explanation: Metals are considered as good thermal conductors because of their lattice structure which has tightly packed ions in it. In the outer shell of atoms the electrons are free to move and thus conduct the electricity but for the polymers, they have a different structure as compared to metals thus it makes it difficult for a polymer to conduct electricity due to high number of discontinuous particle chains. Therefore metals are good conductors , but polymers are not.
Answer:
(a). 575 kJ/kg.
(b). 290kw.
Explanation:
We have the following set of information or parameters from the question above;
Pressure(1) = 100kPa, Pressure (2) = 1MPa, temperature(1) = b1= 12°C = 285K = 285kJ/kg, efficiency = 80% and the mass flow rate of the air = 1kg/s.
At a temperature of 12°C, we have the value from steam table; gx= 1.2, thus gx22 = 1.2 × (1000/100) = 12.
We have that the value for b12 = 517.
Therefore, the value for h2a can be calculated as;
80/100 = (517 - 285)/ (tp at exist) - 285.
0.8 = 232/ (tp at exist) - 285.
232 = 0.8 × (tp at exist) - 285).
232 = 0.8 (tp at exist) - 228 .
(tp at exist) = 575.
Therefore, the temperature 575 kJ/kg.
Thus, the required power input of the compressor = 1kg/s × ( 575 - 285) = 290kw.
<h3>Hey Mate Here Is Your Answer</h3>
Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.
<h3>Hope This Helps You ❤️</h3>
Answer:
See step by step explanations for answer.
Explanation:
600 megawatts =
568 690.272 btu / second
thermal eficiency=work done/Heat supllied
0.38=568690.272/Heat supplied
Heat supplied=1496553.35btu /s
heat emmitted to the atmosphere=heat supplied -work done=(1496553.35-568690.272)=927863.1 btu/s
feed rate=(1496553.35)/12000=124.71 lb/s =10775184.1056 lb/day=5 387.472 ton / day
sulphur content released=(0.03*124.71)/(1.496553)=2.5 lb SO2/million Btu of heat input
so
the degree (%) of sulfur dioxide control needed to meet an emission standard=(2.5/0.15)*100=1666.67 %
the CO2 emission rate=220*(1.496553) =329.241 lb/s =12 903.0802 metric ton / day
