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ziro4ka [17]
2 years ago
8

How does Hydro Technology and Hydro Energy Help with Global Water Issues?

Engineering
1 answer:
GrogVix [38]2 years ago
5 0
It would have environmental and societal impacts
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Calculate the viscosity(dynamic) and kinematic viscosity of airwhen
nikitadnepr [17]

Answer:

(a) dynamic viscosity = 1.812\times 10^{-5}Pa-sec

(b) kinematic viscosity = 1.4732\times 10^{-5}m^2/sec

Explanation:

We have given temperature T = 288.15 K

Density d=1.23kg/m^3

According to Sutherland's Formula  dynamic viscosity is given by

{\mu} = {\mu}_0 \frac {T_0+C} {T + C} \left (\frac {T} {T_0} \right )^{3/2}, here

μ = dynamic viscosity in (Pa·s) at input temperature T,

\mu _0= reference viscosity in(Pa·s) at reference temperature T0,

T = input temperature in kelvin,

T_0 = reference temperature in kelvin,

C = Sutherland's constant for the gaseous material in question here C =120

\mu _0=4\pi \times 10^{-7}

T_0 = 291.15

\mu =4\pi \times 10^{-7}\times \frac{291.15+120}{285.15+120}\times \left ( \frac{288.15}{291.15} \right )^{\frac{3}{2}}=1.812\times 10^{-5}Pa-swhen T = 288.15 K

For kinematic viscosity :

\nu = \frac {\mu} {\rho}

kinemic\ viscosity=\frac{1.812\times 10^{-5}}{1.23}=1.4732\times 10^{-5}m^2/sec

3 0
3 years ago
BE-40 What is a characteristic of a catamaran hull?
Nat2105 [25]

Answer:

<em>A stable ride</em>

Explanation:

A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because,<em> it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. </em>A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.

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3 years ago
One of the flaws in the engineers' reasoning for galloping gertie's design was that they attributed prior failures of suspension
Jlenok [28]
False i think it would be
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3 years ago
A rigid tank contains 2 kg of N2 and 4 kg of Co2 at temperature of 25 C and 1 MPa. Find the partial pressure of each gas respect
lions [1.4K]

Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.

Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:

P_{total} = P_{1}+P_{2}+...

The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:

X_{i} = moles of a gas / total number moles of gas

The rigid tank has total pressure of 1MPa.

  • Nitrogen gas:

molar mass = 14g/mol

mass in the tank = 2000g

number of moles in the tank: n=\frac{2000}{14} = 142.85mols

  • Carbon Dioxide:

molar mass = 44g/mol

mass in the tank = 4000g

number of moles in the tank: n=\frac{4000}{44} = 90.91mols

Total number of moles: 142.85 + 90.91 = 233.76 mols

To calculate partial pressure:

P_{i}=P_{total}.X_{i}

For Nitrogen gas:

P_{N_{2}}=1.\frac{142.85}{233.76}

P_{N_{2}} = 0.6

For Carbon Dioxide:

P_{total}=P_{N_{2}}+P_{CO_{2}}

P_{CO_{2}} = P_{total}-P_{N_{2}}

P_{CO_{2}}=1-0.6

P_{CO_{2}}= 0.4

Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.

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The future goal of health information is appropriate access to ubiquitous, personalized, specific information relevant to the si
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I thinks it’s a A.True
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