Answer:
27009.56 mm
Explanation:
Given:
Diameter of the aluminium alloy bar, d = 12.5 mm
Length of the bar, L = 27 m = 27 × 10³ mm
Tensile force, P = 3 KN = 3 × 10³ N
Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²
Now,
for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:
where, A is the area of the cross-section
or
or
A = 122.718 mm²
on substituting the respective values in the formula, we get
or
δ = 9.56 mm
Hence, the length after the force is applied = L + δ = 27000 + 9.56
= 27009.56 mm
Answer: The answer is A. The company is trying to transfer intellectual capital to a knowledge management system
Answer:
Metal wireways are sheet metal "U"s with removable housing for protecting electrical equipment, wires, and cables.
Explanation:
These are especially used to run wire in manufacturing environments.
Answer:
I believe reverse boost valve.
Answer:
Explanation:
From the question we are told that:
Thickness 
Internal Pressure
Shear stress 
Elastic modulus 
Generally the equation for shear stress is mathematically given by
Where
r_i=internal Radius
Therefore
Generally
Generally the equation for outer diameter is mathematically given by
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is
