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9966 [12]
2 years ago
5

QUICK ASAP

Engineering
1 answer:
Elena-2011 [213]2 years ago
3 0

Answer:

Prosthetics come from the minds of biomedical engineers. They start their projects by consulting with managers, medical professionals and patients. They create initial designs on computer, before developing a prototype that they can test for safety and effectiveness. Several rounds of testing and modification may be necessary before they produce the final prosthetic.QualificationsStudents interested in biomedical engineering begin their education with high-school courses in biology, physics, mathematics, drafting and computers. They continue with a bachelor’s degree in biomedical engineering from an accredited institution. Columbia University offers a typical program of study. The first two years cover general education courses in English, physical education, humanities, math, physics and chemistry. The last two years focus on the engineering specialty, such as biomechanics, which include experiences in the classroom and laboratory. Internships and co-ops, such as with hospitals, can provide the practical experience valued by employers.

mark me brainliest!!

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Three parallel three-phase loads are supplied from a 480V (line-line RMS), 60 Hz three-phase supply. The loads are as follows: L
Travka [436]

Answer:

The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Explanation:

Load 1: Active power P_1 = 20 HP = 14.91kW;

Reactive power Q1 = P tan(\phi)

                               = 14.91\times tan(cos^{-}0.8) = 11.18 kvar


Load 2: Active power P_2 = 20 kW;

Reactive power Q2 = 0 since the load is purely resistive.

Load 3: Active power P_3 = 0 due to purely capacitiveload

           Reactive power Q_3 = -20 Var

a) since all three loads are connected in parallel therefore

    The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Total system reactive power Q = Q_1 + Q_2 + Q_3 = 11.18 + 0 -20 = -8.82 kVar

Since Q = 0, the power factor is unity.

Supply current per phase is given by

I = \frac{P}{\sqrt{3}V_{L}}

= \frac{34910}{\sqrt{3}\times 480} = 41.99 A

5 0
3 years ago
Investiga por que esta simple actividad puede ayudar a mejorar las condiciones ambientales que tu comunidad?
skad [1K]

Creo que por simple actividad hablas de reciclar no?

Espero que sea de ayuda (:

Permite ahorrar energía de forma significativa. Es menos costoso reciclar un material que fabricarlo desde cero, como ocurre por ejemplo con el vidrio.

Reciclar ayuda a evitar la explotación de los recursos naturales. El reciclaje hace posible que los materiales originales puedan ser aprovechados con un nuevo uso, sin que sea necesario volver a usar recursos naturales para fabricarlos.

Se evitan los métodos de extracción de recursos naturales, que son invasivos y contaminantes. El reciclaje permite no sustraer nueva materia prima para fabricación y se puede simplemente reciclar la materia existente.

Se reduce la contaminación, proporcionando una atmósfera más limpia. Reciclando ayudamos a reducir el daño producido al medio ambiente.

Se conserva el medio ambiente ya que permite reducir la cantidad de desechos sólidos que llegan a los vertederos. Esto hace posible que los vertederos ocupen menos espacio e incluso puedan llegar a cerrarse, evitando el impacto negativo que causan sobre el medio ambiente.

Permite alargar la vida útil de los vertederos, ya que se llenan a un menor ritmo evitando que se abran más vertederos.

Si depositamos los desechos que generamos en el contenedor correspondiente para que sean reciclados se reducen los costes de recolección y clasificación de los residuos, ya que son las personas las que ayudan a realizar dicha labor.

En algunos centros de reciclaje ofrecen una compensación económica por llevar material reciclable, como latas y botellas de plástico, por lo que puedes obtener un pequeño ingreso extra reciclando.

7 0
3 years ago
1. (5 pts) An adiabatic steam turbine operating reversibly in a powerplant receives 5 kg/s steam at 3000 kPa, 500 °C. Twenty per
KiRa [710]

Answer:

temperature of first extraction 330.8°C

temperature of second extraction 140.8°C

power output=3168Kw

Explanation:

Hello!

To solve this problem we must use the following steps.

1. We will call 1 the water vapor inlet, 2 the first extraction at 100kPa and 3 the second extraction at 200kPa

2. We use the continuity equation that states that the mass flow that enters must equal the two mass flows that leave

m1=m2+m3

As the problem says, 20% of the flow represents the first extraction for which 5 * 20% = 1kg / s

solving

5=1+m3

m3=4kg/s

3.

we find the enthalpies and temeperatures in each of the states, using thermodynamic tables

Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties

4.we find the enthalpy and entropy of state 1 using pressure and temperature

h1=Enthalpy(Water;T=T1;P=P1)

h1=3457KJ/kg

s1=Entropy(Water;T=T1;P=P1)

s1=7.234KJ/kg

4.

remembering that it is a reversible process we find the enthalpy and the temperature in the first extraction with the pressure 1000 kPa and the entropy of state 1

h2=Enthalpy(Water;s=s1;P=P2)

h2=3116KJ/kg

T2=Temperature(Water;P=P2;s=s1)

T2=330.8°C

5.we find the enthalpy and the temperature in the second extraction with the pressure 200 kPav y the entropy of state 1

h3=Enthalpy(Water;s=s1;P=P3)

h3=2750KJ/kg

T3=Temperature(Water;P=P3;s=s1)

T3=140.8°C

6.

Finally, to find the power of the turbine, we must use the first law of thermodynamics that states that the energy that enters is the same that must come out.

For this case, the turbine uses a mass flow of 5kg / s until the first extraction, and then uses a mass flow of 4kg / s for the second extraction, taking into account the above we infer the following equation

W=m1(h1-h2)+m3(h2-h3)

W=5(3457-3116)+4(3116-2750)=3168Kw

7 0
3 years ago
In a wheatstone bridge three out of four resistors have of 1K ohm each ,and the fourth resistor equals 1010 ohm. If the battery
Dima020 [189]

Answer:

  248.756 mV

  49.7265 µA

Explanation:

The Thevenin equivalent source at one terminal of the bridge is ...

  voltage: (100 V)(1000/(1000 +1000) = 50 V

  impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω

The Thevenin equivalent source at the other terminal of the bridge is ...

  voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V

  impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω

__

The open-circuit voltage is the difference between these terminal voltages:

  (50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage

__

The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:

  (50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA

8 0
3 years ago
Two vertical parallel plates are spaced 0.01 ft apart. If the pressure decreases at a rate of 60 psf/ft in the vertical z-direct
Whitepunk [10]

Answer:

umax = 0.1259ft/s

Explanation:

Given:

•Distance between plates, B = 0.01ft

•Pressure difference decrease, \frac{dp}{dz}=60ps/ft

•Fluid viscosity, u = 10^-³lbf-s/ft²

Specific gravity, S = 0.80

Max velocity in the z-direction will be:

u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}

But h = \frac{P}{y}+z

Substituting for h in the first equation, we have:

\frac{d}{dz}[\frac{p}{y}+z]

\frac{dh}{dz}=\frac{1}{y}\frac{dp}{ds}+\frac{dz}{dz}

= \frac{1}{0.8*62.4}(-60)+1

= -0.20192

Substituting dh/dz value in the first equation (umax), we have:

umax = \frac{0.01^2(0.8*62.4)}{8*10^-^3}(-0.20192)

umax = 0.1259ft/s

4 0
3 years ago
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