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Engineering

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Elena-2011 [213]1 year ago

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Answer:

Prosthetics come from the minds of biomedical engineers. They start their projects by consulting with managers, medical professionals and patients. They create initial designs on computer, before developing a prototype that they can test for safety and effectiveness. Several rounds of testing and modification may be necessary before they produce the final prosthetic.QualificationsStudents interested in biomedical engineering begin their education with high-school courses in biology, physics, mathematics, drafting and computers. They continue with a bachelor’s degree in biomedical engineering from an accredited institution. Columbia University offers a typical program of study. The first two years cover general education courses in English, physical education, humanities, math, physics and chemistry. The last two years focus on the engineering specialty, such as biomechanics, which include experiences in the classroom and laboratory. Internships and co-ops, such as with hospitals, can provide the practical experience valued by employers.

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A spring-loaded piston-cylinder contains 1 kg of carbon dioxide. This system is heated from 104 kPa and 25 °C to 1,068 kPa and 3

labwork [276]

Answer:

Q = -68.859 kJ

Explanation:

given details

mass $co_2 = 1 kg$

initial pressure P_1 = 104 kPa

Temperature T_1 = 25 Degree C = 25+ 273 K = 298 K

final pressure P_2 = 1068 kPa

Temperature T_2 = 311 Degree C = 311+ 273 K = 584 K

we know that

molecular mass of $co_2 = 44$

R = 8.314/44 = 0.189 kJ/kg K

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from ideal gas equation

PV =mRT

$V_1 = \frac{m RT_1}{P_1}$

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$V_1 = 0.5415 m3$

$V_2 = \frac{m RT_2}{P_2}$

$=\frac{1*0.189*584}{1068}$

$V_1 = 0.1033 m3$

WORK DONE

$W =P_{avg}*{V_2-V_1}$

w = 586*(0.1033 -0.514)

W =256.76 kJ

INTERNAL ENERGY IS

$\Delta U = m *c_v*{V_2-V_1}$

$\Delta U = 1*0.657*(584-298)$

$\Delta U =187.902 kJ$

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= 187.902 +(-256.46)

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3 years ago

An inventor claims to have invented a heat engine that operates between the temperatures of 627°C and 27°C with a thermal effici

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Answer Explanation:

the efficiency of the the engine is given by=1- $\frac{T_2}{T_1}$

where T₂= lower temperature

T₁= Higher temperature

we have given efficiency =70%

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higher temperature T₁=627°C=273+627=900K

efficiency=1- $\frac{T_2}{T_1}$

=1- $\frac{300}{900}$

=1-0.3333

=0.6666

=66%

66% is less than 70% so so inventor claim is wrong

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Answer:

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Explanation:

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