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9966 [12]
2 years ago
5

QUICK ASAP

Engineering
1 answer:
Elena-2011 [213]2 years ago
3 0

Answer:

Prosthetics come from the minds of biomedical engineers. They start their projects by consulting with managers, medical professionals and patients. They create initial designs on computer, before developing a prototype that they can test for safety and effectiveness. Several rounds of testing and modification may be necessary before they produce the final prosthetic.QualificationsStudents interested in biomedical engineering begin their education with high-school courses in biology, physics, mathematics, drafting and computers. They continue with a bachelor’s degree in biomedical engineering from an accredited institution. Columbia University offers a typical program of study. The first two years cover general education courses in English, physical education, humanities, math, physics and chemistry. The last two years focus on the engineering specialty, such as biomechanics, which include experiences in the classroom and laboratory. Internships and co-ops, such as with hospitals, can provide the practical experience valued by employers.

mark me brainliest!!

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A closed, 5-m-tall tank is filled with water to a depth of 4 m. The top portion of the tank is filled with air which, as indicat
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Answer:

The pressure that the water exerts on the bottom of the tank is 59.2 kPa

Explanation:

Given;

height of tank, h = 5m

height of water in the tank, h_w = 4m

pressure at the top of the tank, P_{top} = 20 kPa

The pressure exerted by water at the bottom of the tank is the sum of pressure on water surface and pressure due to water column.

P_{bottom} = \gamma h + P_{top}\\\\P_{bottom} = (9.8*10^3*4 \ \ + \ 20*10^3)Pa\\\\P_{bottom} = 59200 \ Pa\\\\P_{bottom} = 59.2 \ kPa

Therefore, the pressure that the water exerts on the bottom of the tank is 59.2 kPa

6 0
3 years ago
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Answer:

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4 0
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Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2
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s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}

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Mass flow rate= \rho\times\dfrac{\pi}{4}d^2V

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mass flow rate=\rho_1A_1V_1

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

                                    =0.12 KW/K

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