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Ira Lisetskai [31]
2 years ago
5

Write down the three formula to find the three types of slope of curve Q with respect to L.

Engineering
2 answers:
mylen [45]2 years ago
8 0

Answer:l=legend

Explanation:basically L = legend and Q=Quick

harina [27]2 years ago
7 0

The three formula for finding out the 3 types of the slope of curve Q with respect to L should be explained below.

<h3>Three formulas:</h3>

1. Slope intercept form where the formula is y = mx + b

Here

y = variable

m = slope of line

x = variable

b = y intercept

2. Point slope form where the formula is y - y1 = m(x - x1)

Here

y = variable

y1 = y coordinate at the first point on line

m = the slope

x = variable

x1 = x coordinate at the first point on line

3. Standard slope form where the formula is ax + by = c

Here

a = x coefficent

b & c = constant term

learn more about formula here: brainly.com/question/24454271

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Supply, demand, global markets, imports and exports, and government Regulation.

Explanation:

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3 years ago
Water vapor at 6 MPa, 600 degrees C enters a turbine operating at steady state and expands to 10kPa. The mass flow rate is 2 kg/
kirill115 [55]

Answer:

Explanation:

Obtain the following properties at 6MPa and 600°C from the table "Superheated water".

h_1=3658.8KL/Kg\\s_1=7.1693kJ/kg.k

Obtain the following properties at 10kPa from the table "saturated water"

h_{f2}=191.81KJ/Kg.K\\h_{fg2}=2392.1KJ/Kg\\s_{f2}=0.6492KJ/Kg.K\\s_{fg2}=7.4996KJ/Kg.K

Calculate the enthalpy at exit of the turbine using the energy balance equation.

\frac{dE}{dt}=Q-W+m(h_1-h_2)

Since, the process is isentropic process Q=0

0=0-W+m(h_1-h_2)\\h_2=h_1-\frac{W}{m}\\\\h_2=3658.8-\frac{2626}{2}\\\\=2345.8kJ/kg

Use the isentropic relations:

s_1=s_{2s}\\s_1=s_{f2}+x_{2s}s_{fg2}\\7.1693=6492+x_{2s}(7.4996)\\x_{2s}=87

Calculate the enthalpy at isentropic state 2s.

h_{2s}=h_{f2}+x_{2s}.h_{fg2}\\=191.81+0.87(2392.1)\\=2272.937kJ/kg

a.)

Calculate the isentropic turbine efficiency.

\eta_{turbine}=\frac{h_1-h_2}{h_1-h_{2s}}\\\\=\frac{3658.8-2345.8}{3658.8-2272.937}=0.947=94.7%

b.)

Find the quality of the water at state 2

since h_f at 10KPa <h_2<h_g at 10KPa

Therefore, state 2 is in two-phase region.

h_2=h_{f2}+x_2(h_{fg2})\\2345.8=191.81+x_2(2392.1)\\x_2=0.9

Calculate the entropy at state 2.

s_2=s_{f2}+x_2.s_{fg2}\\=0.6492+0.9(7.4996)\\=7.398kJ/Kg.K

Calculate the rate of entropy production.

S=\frac{Q}{T}+m(s_2-s_1)

since, Q = 0

S=m(s_2-s_1)\\=2\frac{kg}{s}(7.398-7.1693)kJ/kg\\=0.4574kW/k

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A bicycle has tires that are 26 inches in diameter. The while in motion, the tires rotate through 125 complete revolutions. How
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Answer:

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Explanation:

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