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2 years ago

11

A short true-breeding plant will always produce a short plant. True False

1 answer:

Tanzania [10]2 years ago

4 0

This statement would be considered false.

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A flask contains 6g hydrogen gas and 64 g oxygen at rtp the partial pressure of hydrogen gas in the flask of the total pressure

Alex

Answer:

B.3/5p

Explanation:

For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.

Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.

$P_i=P_t_o_t_a_l*X_i$

Where:

$P_i$ =Partial pressure

$P_t_o_t_a_l$ =Total pressure

$X_i$ =mole fraction

With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:

<u>moles of hydrogen gas</u>

The molar mass of hydrogen gas ( $H_2$ ) is 2 g/mol, so:

$6g~H_2\frac{1~mol~H_2}{2~g~H_2}=~3~mol~H_2$

<u>moles of oxygen gas</u>

The molar mass of oxygen gas ( $O_2$ ) is 32 g/mol, so:

$64g~H_2\frac{1~mol~H_2}{32~g~H_2}=~2~mol~O_2$

Now, total moles are:

Total moles = 2 + 3 = 5

With this value, we can write the partial pressure expression for each gas:

$P_H_2=\frac{3}{5}*P_t_o_t_a_l$

$P_O_2=\frac{2}{5}*P_t_o_t_a_l$

So, the answer would be <u>3/5P</u>.

I hope it helps!

5 0

2 years ago

Rain showers had continued over a particular area for several days. Which of these weather factors is most likely responsible?

krek1111 [17]

Hey Brayden!

Rain showers had continued over a particular area for several days. Which of these weather factors is most likely responsible?

Answer - A Stationary front

Hope This Helps!

If you need anymore help let me know!

8 0

3 years ago

Read 2 more answers

Question 1 (4 points)

oee [108]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Blank # 1 - keep safe distance from the burner

Blank # 2 - Place the equipments on the right place after use

Blank # 3 - perform experiments with proper lab equipment and safety tools

Blank # 4 - Don't break any test tube or lab equipment

(maybe it can be hazardous)

4 0

2 years ago

Umnica [9.8K]

Answer: Volume im pretty sure

3 0

2 years ago

Read 2 more answers

A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca

Phoenix [80]

The specific heat capacity of the metal given the data from the question is 0.66 J/gºC

<h3>Data obtained from the question</h3>

Mass of metal (M) = 76 g
Temperature of metal (T) = 96 °C
Mass of water (Mᵥᵥ) = 120 g
Temperature of water (Tᵥᵥ) = 24.5 °C
Equilibrium temperature (Tₑ) = 31 °C
Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of the metal can be obtained as follow:

Heat loss = Heat gain

MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)

C × 4940 = 3263.52

Divide both side by 4940

C = 3263.52 / 4940

C = 0.66 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

6 0

1 year ago