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3 years ago

7

only a relatively small part of the electromagnetic spectrum is visible. what determines which bands of the electromagnetic spec

trum are invisible to humans?

1 answer:

swat323 years ago

3 0

Answer:

hsnzbssj

Explanation:

<h2>skibbbbbbbbbbbbibi</h2>

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I need help with this question, could you help me? :))) ASAP

Pepsi [2]

Oh ya the correct answer for this is B I think because structure B

4 0

2 years ago

A typical mattress has a network of springs that provide support. If you sit on a mattress, the springs compress. A heavier pers

GenaCL600 [577]

Answer:

Explanation:

Spring has a tendency to store energy in them and deform its shape when force is applied on it. Once the applied force is removed it regains its original shape and size.

It is in helical shape and is used in mattress to give structure and support. Spring have elastic nature and follows spring forces, F = k * x

where is the applied force, k is the spring constant and x is the amount of extension.

When a heavier person sits on a mattress, more weight is applied on springs and they form coils, as weight is removed they regains its shape again.

4 0

3 years ago

What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)

Alenkasestr [34]

Answer:

So percentage error will be 2 %

Explanation:

We have given initial value of acceleration due to gravity $g=10m/sec^2$

And final value of acceleration due to gravity $g=9.8m/sec^2$

We have to find the percentage error

We know that percentage error is given by $percentage\ error=\frac{initial\ value-final\ value}{initial\ value}\times 100$

So $percentage\ error=\frac{10-9.8}{10}\times 100=2$ %

4 0

3 years ago

Acceleration is always act in the direction of

hjlf

Answer:

Acceleration acts always in the direction. Of the displacement. Of the initial velocity.

5 0

3 years ago

A ski hill is angled 20° above the horizontal. If a skier starts from rest at the top of the hill, how fast will she be travelin

MaRussiya [10]

Answer:

20 m/s

Explanation:

First, we calculate for the acceleration down the incline using $a = gsin\theta$ .

a = (9.80)sin(20°)

a = 3.35

Then, we use one of the kinematics equations, ${v_{f}}^{2} = {v_{i}}^{2} + 2 a\Delta s$ .

$v_{i}$ = 0 m/s

a = 3.35

$\Delta s$ = 62 m

$v_{f} = \sqrt{2(3.35)(62)}$

$v_{f} =20.381 = 20 m/s$

6 0

2 years ago