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Drupady [299]
4 years ago
9

By which method does the following move into the cell: movement of oxygen, carbon dioxide, and other small uncharged molecules a

cross the membrane
Physics
1 answer:
Gwar [14]4 years ago
3 0
Oxygen, Carbon dioxide and other small uncharged molecules can move through the cell membrane through a method called osmosis 
osmosis is when there is a semipermeable membrane and molecules pass through it, where there is less concentration of molecules.
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A hole of radius r is bored through the center of a sphere of radius r. Find the volume v of the remaining portion of the sphere
nikklg [1K]

Answer:

Πr²(4r/3 - h)

Explanation:

Volume of a sphere is 4/3Πr³. If a hole of radius r is bored through, the hole with generate a circular shape in the sphere. The volume of the remaining portion of the sphere will be the difference between the volume of the sphere and the area of the hole bored(which will be volume of a cylinder since the hole bored will create a cylindrical shape in the sphere)

Area of the remaining portion = Volume of sphere - volume of a cylinder

Volume of sphere = 4/3Πr³

Volume of a cylinder = Πr²h

Volume of the remaining portion = 4/3Πr³ - Πr²h

= Πr²(4r/3 - h)

Where h is the height of the cylindrical hole

5 0
3 years ago
Read 2 more answers
A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
3 years ago
Which forms of energy are involved when you turn on a desk lamp and the bulb<br> becomes hot?
alukav5142 [94]

Answer:

Electric energy moves through the wire to the lamp's bulb. In the bulb, electric energy transforms into thermal energy and light energy.

Explanation:

4 0
3 years ago
A force of 120 N is exerted on a 40 kg container which sits on a floor. If the frictional force between floor and container is 8
harkovskaia [24]

Answer:

Magnitude is 144N .

Explanation:

a²+b²=c²

120N²+80N²=c²

14400+6400=c²

\sqrt{20800}   =  \sqrt{c} ^{2}

144N=c

7 0
3 years ago
An aluminium object has a mass of 27kg and density of 2700 the object is atached to a spring and immerged in a tank of water det
laiz [17]

Answer:

0.01m^3

Explanation:

m=27

density=2700

density=mass/volume

2700=27/volume

volume=27/2700=0.01

8 0
2 years ago
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