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Trava [24]
3 years ago
14

What are the products of the combustion of a hydrocarbon?

Chemistry
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

carbon dioxide and water

Keith_Richards [23]3 years ago
8 0

Answer:

The answer is C I just took the test and got a 100.

Explanation:

Have an amazing day and do a great job on your school work : )

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Why are tables and graphs useful for organizing scientific data?
tatuchka [14]

Answer:

Since most of the data scientist collect is quantitative, data tables and charts are usually used to organize the information • Graphs are created from data tables • They can allow the investigator to get a visual image of the observations, which simplifies interpretation and drawing conclusions • Valid conclusions depend

8 0
2 years ago
Which one of the following is not a compound?
DaniilM [7]

Answer:

Marble.

Explanation:

8 0
2 years ago
Read 2 more answers
How does a buffer resist change in pH upon addition of a strong acid? The strong acid reacts with the strong base in the buffer
MrRa [10]

Answer:

The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH.

Explanation:

When a strong acid is added to the buffer, the acid dissociates and furnish hydrogen ions which combine with the conjugate of the weak acid, forming weak acid. The weak acid dissociates to only some extent and can furnish only some protons and there is no significant change in the pH.

Hence, option B is correct.

4 0
2 years ago
Yo mismo no hablo español, así que espero que esto sea realmente legible--
Deffense [45]

Answer:

what

Explanation:

4 0
3 years ago
Read 2 more answers
PV = nRT. If P = 1 atm, V = 5.0 liter, R = 0.0821 L.atm/mol.K, and T = 293 K; what is the value of n?
Leya [2.2K]

Answer:

n = 0.207 mole

Explanation:

We have,

P = 1 atm

V = 5 liter

R = 0.0821 L.atm/mol.K

T = 293 K

We need to find the value of n. The relation is as follows :

PV = nRT

Solving for n,

n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 5}{0.0821 \times 293}\\\\n=0.207\ \text{mol}

So, the value of n is 0.207 mol.

6 0
2 years ago
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