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3 years ago

What are the products of the combustion of a hydrocarbon?

Chemistry

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

carbon dioxide and water

Keith_Richards [23]3 years ago

8 0

Answer:

The answer is C I just took the test and got a 100.

Explanation:

Have an amazing day and do a great job on your school work : )

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Antacids work to relieve stomach acids because of which of the following types of reactions?

Anastaziya [24]

Answer: The correct answer is Option B.

Explanation:

Decomposition is a type of chemical reaction in which larger compound breaks down into two or more smaller compounds.

$AB\rightarrow A+B$

Double displacement reactions is defined as the chemical reaction in which exchange of ions takes place.

$AB+CD\rightarrow AD+CB$

Synthesis reaction is a type of reaction in which two or more smaller compounds combines to form a single large compound.

$A+B\rightarrow AB$

Single displacement reaction is a type of reaction in which a more reactive metal displaces a less reactive metal from its chemical reaction.

$A+BC\rightarrow AC+B$

In stomach, an acid is present known as hydrochloric acid and to neutralize its effect, antacid is taken which has $CaCO_$ as a component.

The reaction between HCl and $CaCO_3$ is a type of neutralization reaction and it is a type of double displacement reaction.

The equation between the two follows:

$CaCO_3+HCl\rightarrow CaCl_2+H_2O+CO_2$

Hence, the correct answer is Option B.

4 0

3 years ago

What is20 grams of HNO^3

morpeh [17]

63.01284*20=1260.568

7 0

3 years ago

Read 2 more answers

A negative △H means an exothermic reaction. True False

Nostrana [21]

Your answer is False I think

6 0

3 years ago

If the mass of a liquid reactant is 10g and the mass of a powder reactant is 5g then what should the mass of the product be acco

guapka [62]

Answer:15g

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

10g + 5g ➡️ 15g

6 0

3 years ago

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago